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Why Does My Fahrenheit to Celsius Conversion Program Output 0?

Susan Sarandon
Susan SarandonOriginal
2024-10-25 02:47:02198browse

Why Does My Fahrenheit to Celsius Conversion Program Output 0?

Why Does This C Program Convert Fahrenheit to Celsius Incorrectly?

A C program that attempts to convert Fahrenheit temperatures to Celsius is causing confusion due to an incorrect output of 0. Let's delve into the code and explain the issue.

The program begins by including the necessary standard input and output library and defines some variables.

<code class="cpp">#include <iostream>
using namespace std;

float celsius;
float fahrenheit;</code>

The code then prompts the user to input a Celsius temperature and stores it in the celsius variable.

<code class="cpp">cout << "Enter Celsius temperature: ";
cin >> celsius;</code>

The computation for converting Celsius to Fahrenheit is as follows:

<code class="cpp">fahrenheit = (5/9) * (celsius + 32);</code>

The issue arises here. The expression (5/9) performs integer division by default, resulting in 0. To obtain the correct fractional result, we need to cast one of the operands to a floating-point type.

<code class="cpp">fahrenheit = (5.0/9) * (celsius + 32);</code>

By using floating-point division, we ensure the computation is done correctly and the fractional part is preserved.

The program concludes by outputting the Fahrenheit temperature.

<code class="cpp">cout << "Fahrenheit = " << fahrenheit << endl;</code>

By making this correction, the program will now correctly convert and display Fahrenheit temperatures based on user-provided Celsius values.

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