


Understanding Recursion in Python: Summing List Integers
Recursion is a programming technique where a function calls itself repeatedly to solve smaller instances of a problem until a base condition is reached. In Python, we can apply recursion to various tasks, including calculating sums of list integers.
Recursive Function: listSum
To define a recursive function listSum that takes a list of integers and returns their sum, we can break down the problem as follows:
- Base Condition: If the list is empty (list == []), the sum is 0.
- Recursive Step: If the list is not empty, the sum is the first element (list[0]) plus the sum of the remaining elements (listSum(list[1:])).
Simple Version:
<code class="python">def listSum(ls): # Base condition if not ls: return 0 # First element + result of calling `listsum` with rest of the elements return ls[0] + listSum(ls[1:])</code>
Tail Call Recursion:
To improve efficiency, we can pass the current sum to the function parameter:
<code class="python">def listSum(ls, result): # Base condition if not ls: return result # Call with next index and add the current element to result return listSum(ls[1:], result + ls[0])</code>
Passing Around Index Version:
To avoid creating intermediate lists, we can pass the index of the current element:
<code class="python">def listSum(ls, index, result): # Base condition if index == len(ls): return result # Call with next index and add the current element to result return listSum(ls, index + 1, result + ls[index])</code>
Inner Function Version:
To simplify code, we can define a recursive inner function:
<code class="python">def listSum(ls): def recursion(index, result): # Base condition if index == len(ls): return result # Call with next index and add the current element to result return recursion(index + 1, result + ls[index]) return recursion(0, 0)</code>
Default Parameters Version:
Using default parameters, we can simplify further:
<code class="python">def listSum(ls, index=0, result=0): # Base condition if index == len(ls): return result # Call with next index and add the current element to result return listSum(ls, index + 1, result + ls[index])</code>
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