How to Elegantly Compare Arrays of Objects in JavaScript

Comparing Arrays of Objects in JavaScript: A More Elegant Approach

While brute force methods can be effective in comparing arrays of objects, often there are more elegant solutions. In JavaScript, comparing arrays of objects requires careful consideration due to the dynamic nature of object properties.

However, there is a concise technique to tackle this problem:

<code class="js">const objectsEqual = (o1, o2) =>
    Object.keys(o1).length === Object.keys(o2).length 
        && Object.keys(o1).every(p => o1[p] === o2[p]);</code>

This function, objectsEqual, compares two objects by first checking the number of properties they have. If they differ, the objects cannot be considered equal.

Next, it examines each property of the first object (p) and verifies that its value matches the corresponding property value in the second object. If any property values differ, the objects are not equal.

For example:

<code class="js">const obj1 = { name: 'John', age: 33};
const obj2 = { age: 33, name: 'John' };
const obj3 = { name: 'John', age: 45 };
        
console.log(objectsEqual(obj1, obj2)); // true
console.log(objectsEqual(obj1, obj3)); // false</code>

This solution efficiently compares arrays of objects, taking into account the variable number of properties and ensuring accurate value matching.

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