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HomeWeb Front-endJS TutorialHow to Resolve the \'No Multipart Boundary\' Error in Ajax XMLHttpRequest File Upload?

How to Resolve the

Upload Files with Ajax XMLHttpRequest: Resolving the "No Multipart Boundary" Error

When attempting to upload files using XMLHttpRequest, you may encounter the "The request was rejected because no multipart boundary was found" error. To address this issue, let's delve into the provided code and identify the potential causes.

The following code snippet is intended to upload a file using XMLHttpRequest:

<code class="javascript">var url = "http://localhost:80/...";
$(document).ready(function(){
    document.getElementById('upload').addEventListener('change', function(e) {
        var file = this.files[0];
        var xhr = new XMLHttpRequest();
        // xhr.file = file; // not necessary if you create scopes like this
        xhr.addEventListener('progress', function(e) {
            var done = e.position || e.loaded, total = e.totalSize || e.total;
            console.log('xhr progress: ' + (Math.floor(done/total*1000)/10) + '%');
        }, false);
        if ( xhr.upload ) {
            xhr.upload.onprogress = function(e) {
                var done = e.position || e.loaded, total = e.totalSize || e.total;
                console.log('xhr.upload progress: ' + done + ' / ' + total + ' = ' + (Math.floor(done/total*1000)/10) + '%');
            };
        }
        xhr.onreadystatechange = function(e) {
            if ( 4 == this.readyState ) {
                console.log(['xhr upload complete', e]);
            }
        };
        xhr.open('post', url, true);
        xhr.setRequestHeader("Content-Type", "multipart/form-data");
        xhr.send(file);
    }, false);
});</code>

To resolve the aforementioned error, two key points need to be addressed:

  1. The line xhr.file = file; is redundant and unnecessary. It's not required to attach the file object in this manner.
  2. The actual issue lies in the line xhr.send(file). To correctly upload the file, it needs to be wrapped in a FormData object, which will format it into a multipart/form-data POST data object. The updated code should look like this:
<code class="javascript">...
var formData = new FormData();
formData.append("thefile", file);
xhr.send(formData);
...</code>

By creating a FormData object and appending the file, you ensure that the data is correctly structured and ready to be processed on the server. The file will now be accessible in $_FILES['thefile'] (if you are using PHP on the server-side), allowing you to handle it appropriately.

Referring to documentation resources such as MDC and Mozilla demos can provide valuable guidance when faced with such issues.

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