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Trying to develop an android application using python and kivymd..
can anyone help me solve the error in the following code file
code --
from kivy.animation import Animation
from kivy.clock import Clock
from kivymd.app import MDApp
from kivy.uix.image import Image
from kivymd.uix.screenmanager import ScreenManager
from kivy.uix.screenmanager import Screen
class SplashScreen(Screen):
def on_enter(self): self.animate_logo() Clock.schedule_once(self.transition_to_main_screen, 3) # Adjust transition time as needed def animate_logo(self): logo_image = self.logo_image if logo_image: anim = Animation(size_hint_x=1.2, duration=0.5) anim.bind(on_complete=self.animate_logo_back) anim.start(logo_image) def animate_logo_back(self, *args): logo_image = self.logo_image if logo_image: anim = Animation(size_hint_x=1, duration=0.5) anim.start(logo_image) def transition_to_main_screen(self, dt): self.manager.current = 'main_screen' # Replace 'main_screen' with your main screen name
class MainScreen(Screen):
# ... (Other screen logic)
def login(self): # Implement your login logic here username = self.ids.username_field.text password = self.ids.password_field.text # ... (Check credentials, navigate to appropriate screen) def show_signup_screen(self): self.manager.current = 'signup_screen' # Replace with your signup screen name
class MainApp(MDApp):
# ... (Other app logic)
def build(self): sm = ScreenManager() sm.add_widget(SplashScreen(name='splash_screen')) sm.add_widget(MainScreen(name='main_screen')) # Add your main screen sm.current = 'splash_screen' return sm
if name == 'main':
MainApp().run() # Ensure app runs only when executed as a script
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