Home >Java >javaTutorial >Common Interview Question: Swapping Two Numbers Without a Temporary Variable in Java
Swapping two numbers is a common task in programming interviews, and there are various ways to achieve this. One interesting method is to swap two numbers without using a temporary variable. This technique is not only clever but also helps in understanding arithmetic operations in Java. In this article, we will explore this method and provide a sample code implementation.
The idea behind swapping two numbers without a temporary variable is based on basic arithmetic operations. The core idea is to use addition and subtraction to perform the swap. Here's how it works:
Here's a simple Java program that demonstrates this method:
package basics; public class SwapTwoNumbersWithoutTemp { private void swapNumbers(int a, int b) { a = a + b; // Step 1: a becomes the sum of a and b b = a - b; // Step 2: b becomes the original value of a a = a - b; // Step 3: a becomes the original value of b System.out.println("a = " + a + " b = " + b); } public static void main(String[] args) { SwapTwoNumbersWithoutTemp swap = new SwapTwoNumbersWithoutTemp(); swap.swapNumbers(5, 6); } }
Swapping two numbers without a temporary variable is an efficient and clever technique often asked in interviews. This method not only saves memory but also showcases your understanding of basic arithmetic operations. It can be a great addition to your coding toolbox, especially for interview preparation.
Feel free to experiment with this code and test different pairs of numbers to see how the method performs!
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Check out my series on Array Interview Essentials for more tips and insights into Java programming.
Happy Coding!
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