timeit.repeat - playing with repetitions to understand patterns

1. The problem

Over your software engineering career, you might encounter a piece of code that performs poorly, taking way longer than acceptable. To make matters worse, the performance is inconsistent and quite variable across multiple executions.

At this point in time, you would have to accept that when it comes to software performance, there is a lot of non-determinism at play. The data can be distributed within a window and sometimes follows a normal distribution. Other times, it can be erratic with no obvious patterns.

2. The approach

This is when benchmarking comes into play. Executing your code five times is good, but at the end of the day, you have just five data points, with too much value placed on each data point. We need to have a much bigger number of repetitions of the same code block to see a pattern.

3. The question

How many data points should one have? Much has been written about it, and one of the papers I covered

Rigorous performance evaluation requires benchmarks to be built,
executed and measured multiple times in order to deal with random
variation in execution times. Researchers should provide measures
of variation when reporting results.

Kalibera, T., & Jones, R. (2013). Rigorous benchmarking in reasonable time. Proceedings of the 2013 International Symposium on Memory Management. https://doi.org/10.1145/2491894.2464160

When measuring performance, we might want to measure CPU, memory, or disk usage to get a broader picture of the performance. It is usually best to start with something simple, like time elapsed, since it is easier to visualize. A 17% CPU usage doesn't tell us much. What should it be? 20% or 5? CPU Usage is not one of the natural ways in which humans perceive performance.

4. The experiment

I am going to use python's timeit.repeat method to repeat a simple code execution block. The code block just multiplies numbers from 1 to 2000.

from functools import reduce
reduce((lambda x, y: x * y), range(1, 2000))

This is the method signature

(function) def repeat(
    stmt: _Stmt = "pass",
    setup: _Stmt = "pass",
    timer: _Timer = ...,
    repeat: int = 5,
    number: int = 1000000,
    globals: dict[str, Any] | None = None
) -> list[float]

What are repeat and number?

Let's start with number. If the code block is too small, it will terminate so quickly that you would not be able to measure anything. This argument mentions the number of times the stmt has to be executed. You can consider this as the new code block. The float returned is for stmt X number execution time.

In our case, we will keep number as 1000 since multiplication up to 2000 is expensive.

Next, move on to repeat. This specifies the number of repetitions or the number of times the above block has to be executed. If repeat is 5, then the list[float] returns 5 elements.

Let's start with creating a simple execution block

def run_experiment(number_of_repeats, number_of_runs=1000):
    execution_time = timeit.repeat(
        "from functools import reduce; reduce((lambda x, y: x * y), range(1, 2000))",
        repeat=number_of_repeats,
        number=number_of_runs
    )
    return execution_time

We want to execute it in different repeat values

repeat_values = [5, 20, 100, 500, 3000, 10000]

The code is pretty simple and straightforward

5. Exploring the Results

Now we reach the most important part of the experiment - which is to interpret data. Please be advised, that different people can interpret it differently and there is no single correct answer.

Your definition of correct answer depends a lot on what you are trying to achieve. Are you concerned with the performance degradation of 95% of your users? Or, are you worried about performance degradation of the tail 5% of your users who are quite vocal?

5.1. Execution Time Analysis Statistics for multiple values of repeat

As we can see, the min and max time are whacky. It shows how one datapoint can be enough to change the value of mean. The worst part is that high min and high max are for different value of repeats. There is no correlation and it just showcases the power of outliers.

Next we move to median and notice that as we increase number of repeats, the median goes down, except for 20. What can explain it? It just shows how smaller number of repeats implies that we don't necessarily get the full breath of possible values.

Moving to truncated mean, where the lowest 2.5% and highest 2.5% are trimmed off. This is useful when you don't care about outlier users and want to to focus on the performance of the middle 95% of your users.

Beware, trying to improve the performance of the middle 95% of the users carries the possibility of degrading the performance of the outlier 5% of the users.

5.2. Execution Time Distribution for multiple values of repeat

Next we want to see where all the data lies. We would use histogram with bin of 10 to see where the data falls. With repetitions of 5 we see that they are mostly equally spaced. This is not one usually expects as sampled data should follow a normal looking distribution.

In our case the value is bounded on the lower side and unbounded on the upper side, since it will take more than 0 seconds to run any code, but there is no upper time limit. This means our distribution should look like a normal distribution with a long right tail.

Going forward with higher values of repeat, we see a tail emerging on the right. I would expect with higher number of repeat, there would be a single histogram bar, which is tall enough that outliers are overshadowed.

5.3. Execution Time Distribution for values 1000 and 3000

How about we look at larger values of repeat to get a sense? We see something unusual. With 1000 repeats, there are a lot of outliers past 1.8 and it looks a lot more tighter. The one on the right with 3000 repeat only goes upto 1.8 and has most of its data clustered around two peaks.

What can it mean? It can mean a lot of things including the fact that sometimes maybe the data gets cached and at times it does not. It can point to many other side effects of your code, which you might have never thought of. With the kind of distribution of both 1000 and 3000 repeats, I feel the TM95 for 3000 repeat is the most accurate value.

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6. Appendix

6.1. Code

import timeit
import matplotlib.pyplot as plt
import json
import os
import statistics
import numpy as np

def run_experiment(number_of_repeats, number_of_runs=1000):
    execution_time = timeit.repeat(
        "from functools import reduce; reduce((lambda x, y: x * y), range(1, 2000))",
        repeat=number_of_repeats,
        number=number_of_runs
    )
    return execution_time

def save_result(result, repeats):
    filename = f'execution_time_results_{repeats}.json'
    with open(filename, 'w') as f:
        json.dump(result, f)

def load_result(repeats):
    filename = f'execution_time_results_{repeats}.json'
    if os.path.exists(filename):
        with open(filename, 'r') as f:
            return json.load(f)
    return None

def truncated_mean(data, percentile=95):
    data = np.array(data)
    lower_bound = np.percentile(data, (100 - percentile) / 2)
    upper_bound = np.percentile(data, 100 - (100 - percentile) / 2)
    return np.mean(data[(data >= lower_bound) & (data <= upper_bound)])

# List of number_of_repeats to test
repeat_values = [5, 20, 100, 500, 1000, 3000]

# Run experiments and collect results
results = []
for repeats in repeat_values:
    result = load_result(repeats)
    if result is None:
        print(f"Running experiment for {repeats} repeats...")
        try:
            result = run_experiment(repeats)
            save_result(result, repeats)
            print(f"Experiment for {repeats} repeats completed and saved.")
        except KeyboardInterrupt:
            print(f"\nExperiment for {repeats} repeats interrupted.")
            continue
    else:
        print(f"Loaded existing results for {repeats} repeats.")

    # Print time taken per repetition
    avg_time = statistics.mean(result)
    print(f"Average time per repetition for {repeats} repeats: {avg_time:.6f} seconds")

    results.append(result)

trunc_means = [truncated_mean(r) for r in results]
medians = [np.median(r) for r in results]
mins = [np.min(r) for r in results]
maxs = [np.max(r) for r in results]

# Create subplots
fig, axs = plt.subplots(2, 2, figsize=(15, 12))
fig.suptitle('Execution Time Analysis for Different Number of Repeats', fontsize=16)

metrics = [
    ('Truncated Mean (95%)', trunc_means),
    ('Median', medians),
    ('Min', mins),
    ('Max', maxs)
]

for (title, data), ax in zip(metrics, axs.flatten()):
    ax.plot(repeat_values, data, marker='o')
    ax.set_title(title)
    ax.set_xlabel('Number of Repeats')
    ax.set_ylabel('Execution Time (seconds)')
    ax.set_xscale('log')
    ax.grid(True, which="both", ls="-", alpha=0.2)

    # Set x-ticks and labels for each data point
    ax.set_xticks(repeat_values)
    ax.set_xticklabels(repeat_values)

    # Rotate x-axis labels for better readability
    ax.tick_params(axis='x', rotation=45)

plt.tight_layout()

# Save the plot to a file
plt.savefig('execution_time_analysis.png', dpi=300, bbox_inches='tight')
print("Plot saved as 'execution_time_analysis.png'")

# Create histograms for data distribution with 10 bins
fig, axs = plt.subplots(2, 3, figsize=(20, 12))
fig.suptitle('Data Distribution Histograms for Different Number of Repeats (10 bins)', fontsize=16)

for repeat, result, ax in zip(repeat_values, results, axs.flatten()):
    ax.hist(result, bins=10, edgecolor='black')
    ax.set_title(f'Repeats: {repeat}')
    ax.set_xlabel('Execution Time (seconds)')
    ax.set_ylabel('Frequency')

plt.tight_layout()

# Save the histograms to a file
plt.savefig('data_distribution_histograms_10bins.png', dpi=300, bbox_inches='tight')
print("Histograms saved as 'data_distribution_histograms_10bins.png'")

# Create histograms for 1000 and 3000 repeats with 30 bins
fig, axs = plt.subplots(1, 2, figsize=(15, 6))
fig.suptitle('Data Distribution Histograms for 1000 and 3000 Repeats (30 bins)', fontsize=16)

for repeat, result, ax in zip([1000, 3000], results[-2:], axs):
    ax.hist(result, bins=100, edgecolor='black')
    ax.set_title(f'Repeats: {repeat}')
    ax.set_xlabel('Execution Time (seconds)')
    ax.set_ylabel('Frequency')

plt.tight_layout()

# Save the detailed histograms to a file
plt.savefig('data_distribution_histograms_detailed.png', dpi=300, bbox_inches='tight')
print("Detailed histograms saved as 'data_distribution_histograms_detailed.png'")

plt.show()

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