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Type assertion is implemented through the following steps: The compiler generates a runtime.type structure containing type information and method tables. When type-asserting a value, the compiler checks whether its runtime.type structure matches the target type. When the match succeeds, the type assertion succeeds, ok is true, and the value is extracted. When the match fails, the type assertion fails, ok is false, and value is set to nil.
#How are type assertions implemented in Go functions?
Type assertions allow us to check whether a value belongs to a certain type and extract its value. It is implemented using the interface{}
and type
keywords.
Syntax
The syntax of type assertion is as follows:
value, ok := value.(type)
Where:
value
Is the value to be type-asserted. type
is the type to check. ok
is a Boolean value that tells us whether the type assertion is successful. When ok
is true
, value
belongs to the specified type and we can access its actual value in value
. When ok
is false
, the type assertion fails and value
is nil
. Implementation
Under the hood, type assertions are implemented through the following steps:
runtime .type
structure, which contains type information and method tables. runtime.type
structure matches the target type's runtime.type
structure. ok
is true
, and the actual value of the value is stored in value
. ok
is false
, and value
is set to nil
. Practical case
The following is a practical example of using type assertions:
package main import "fmt" func main() { var value interface{} = 42 if i, ok := value.(int); ok { fmt.Println("Value is of type int and its value is:", i) } else { fmt.Println("Value is not of type int") } }
Result:
Value is of type int and its value is: 42
Note:
value
will be set to nil
, even if the original value was not nil
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