"$id","name"=>"$name","singer"=>"$sing"/> "$id","name"=>"$name","singer"=>"$sing">
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HomeBackend DevelopmentPHP Tutorial关于PHP循环生成数组的有关问题,望们赐教。

关于PHP循环生成数组的问题,望大虾们赐教。。。。
做了一个音乐搜索的接口,想要输出JSON格式

返回的单条数据是:

$arr = array("url"=>"$id","name"=>"$name","singer"=>"$singer","album"=>"$album") ;

怎么样把所有的数据循环成一个二维数组(是二维吗?)

输出如下格式的JSON

"list":[{"Song":" 歌曲名 ","Name":" 歌手 ","Album":" 专辑 一般为空 "},{…………}]

然后,最后会把数组json_encode 输出来!

------解决方案--------------------

PHP code
//数据构造为下面这种形式的数组$ar = array('List' => array(    0 => array('Song' => 's1', 'Name' => 'n1'),    1 => array('Sone' => 's2', 'Name' => 'n2')));echo json_encode($ar);<br><font color="#e78608">------解决方案--------------------</font><br>你的json 数据和 数组关系在什么地方?<br>"list":[{"Song":" 歌曲名 ","Name":" 歌手 ","Album":" 专辑 一般为空 "},{…………}]<br><br>Song=name? name=singer?<br><br>$arr = array("url"=>"0","name"=>"旧情绵绵","singer"=>"张学友","album"=>"雪狼湖") ;<br>$arr2 = array("url"=>"1","name"=>"狮子座","singer"=>"曾哥","album"=>"信曾哥") ;<br>$arr3 = array("url"=>"2","name"=>"我的","singer"=>"春哥","album"=>"信春哥上本科") ;<br><br>$array[]=$arr;<br>$array[]=$arr2;<br>$array[]=$arr3;<br><br>echo json_encode($array,JSON_UNESCAPED_UNICODE);<br><br>php 5.4+UTF8<br><font color="#e78608">------解决方案--------------------</font><br>建立一个数组,然后使用array_push()加数据,再转换成你要的东西。<div class="clear">
                 
              
              
        
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