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How to use RPC to upload files in Golang?

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WBOYOriginal
2024-06-01 13:47:551127browse

Use RPC to implement file upload: Create an RPC server to handle file upload requests, created using the net/rpc package. Create an RPC client to initiate file upload requests to the server, created using the net/rpc package, serialize the file and send it via an RPC call.

如何在 Golang 中使用 RPC 实现文件上传?

How to use RPC to implement file upload in Go

Remote Procedure Call (RPC) is a method in distributed systems The mechanism for achieving communication. It allows clients to call a function located on a different machine as if it were a local function. This article will introduce how to use RPC in Go to implement file upload.

Create RPC Server

First, we need to create the RPC server that will handle file upload requests from clients. A simple RPC server can be created using the net/rpc package:

// 建立一个 RPC 服务
type FileUploadServer struct {}

// 注册 FileUploadServer 服务
func RegisterFileUploadServer(s *rpc.Server) {
    s.Register(new(FileUploadServer))
}

// 定义 UploadFile 方法
func (s *FileUploadServer) UploadFile(file *File, reply *FileResponse) error {

    // TODO: 实际的文件上传逻辑

}

Create RPC client

Next, we create the RPC client , it will initiate a file upload request to the server:

// 导入所需包
import (
    "net/rpc"
    "os"
)

// 定义 FileUploadClient 客户端
type FileUploadClient struct {
    conn   *rpc.Client
    path   string
    file   *os.File
}

// 创建 FileUploadClient 客户端
func NewFileUploadClient(path string) (*FileUploadClient, error) {

    // 连接到 RPC 服务器
    conn, err := rpc.Dial("tcp", "localhost:8080")

    // 返回 FileUploadClient 客户端
    return &FileUploadClient{
        conn:   conn,
        path:   path,
    }, err
}

// 上传文件
func (c *FileUploadClient) UploadFile() error {

   // 打开文件
   file, err := os.Open(c.path)

   // 序列化文件并通过 RPC 调用发送
   return c.conn.Call("FileUploadServer.UploadFile", &File{Data: file}, &FileResponse{})
}

Practical case

The following is a practical case showing how to use Golang RPC to implement file upload:

// 服务端代码
package main

import (
    "net"
    "net/rpc"
    os"
)

type FileUploadServer struct {}

func RegisterFileUploadServer(s *rpc.Server) {
    s.Register(new(FileUploadServer))
}

func (s *FileUploadServer) UploadFile(file *File, reply *FileResponse) error {
    
    // 将文件保存到本地
    f, err := os.Create("./" + file.Name)

    if err != nil {
        return err
    }
    
    _, err = f.Write(file.Data)

    return err
}

func main() {
    // 创建 RPC 服务器并注册服务
    rpc.RegisterName("FileUploadServer", new(FileUploadServer))

    // 监听指定端口
    listener, err := net.Listen("tcp", ":8080")

    if err != nil {
        log.Fatal(err)
    }
    
    // 接受 RPC 连接并处理请求
    rpc.Accept(listener)
}

// 客户端代码
package main

import (
    "log"
    "net/rpc"
    "os"
)

type File struct {
    Name string
    Data []byte
}

type FileResponse struct {}

func main() {
    // 创建 RPC 客户端
    client, err := rpc.Dial("tcp", "localhost:8080")

    if err != nil {
        log.Fatal(err)
    }

   // 打开要上传的文件
   file, err := os.Open("./test.txt")

   if err != nil {
        log.Fatal(err)
    }
    
    // 序列化文件并通过 RPC 调用发送
   if err = client.Call("FileUploadServer.UploadFile", &File{Name: "test.txt", Data: file}, &FileResponse{}); err != nil {
        log.Fatal(err)
   }
   
   log.Println("文件上传成功")
}

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