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Three ways to remove duplicates from arrays in JavaScript_javascript tips

WBOY
WBOYOriginal
2016-05-16 15:04:301107browse

No more nonsense, the specific method is as follows:

Method 1: Return the new array and the type of each bit remains unchanged

function outRepeat(a){
      var hash=[],arr=[];
      for (var i = 0; i < a.length; i++) {
        hash[a[i]]!=null;
        if(!hash[a[i]]){
          arr.push(a[i]);
          hash[a[i]]=true;
        }
      }
      console.log(arr);
    }
    outRepeat([2,4,4,5,"a","a"]);//[2, 4, 5, "a"] 

Method 2: Similar to method 1, but I think method 1 is easier to understand

function outRepeat(a){
      var hash=[],arr=[];
      for (var i = 0,elem;(elem=a[i])!=null; i++) {
        if(!hash[elem]){
          arr.push(elem);
          hash[elem]=true;
        }
      }
      console.log(arr);
    }
    outRepeat([2,4,4,5,"a","a"]);//[2, 4, 5, "a"] 

Method 3: Easier to understand than the first two, but the number type of each position in the returned new array changes to string type! ! Critical moments have to be dealt with

function outRepeat(a){
      var hash=[],arr=[];
      for (var i = 0; i < a.length; i++) {
        hash[a[i]]=null;
      }
      for(var key in hash){
          arr.push(key);        
        }
      console.log(arr);
    }
    outRepeat([2,4,4,5,"a","a"]);//["2", "4", "5", "a"]

The above are the three methods that the editor introduced to you to remove duplicates from arrays in JavaScript. I hope it will be helpful to you!

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