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关于mysql修改,该如何解决

WBOY
WBOYOriginal
2016-06-13 10:11:19902browse

关于mysql修改
ALTER TABLE pre_forum_attachment CHANGE 'aid' 'aid' mediumint(8) unsigned NOT NULL AUTO_INCREMENT
执行不了怎么回事,提示错误是#1264 - Out of range value adjusted for column 'aid' at row 3 


------解决方案--------------------
bigint
从 -2^63 (-9223372036854775808) 到 2^63-1 (9223372036854775807) 的整型数据(所有数字)。存储大小为 8 个字节。

mediumint
带符号的范围是-8388608到8388607,无符号的范围是0到16777215,使用3个字节。
无符号的范围是0到16777215

由于 mediumint 的存储范围远小于 bigint,所以必然导致溢出
主键必须是唯一的
------解决方案--------------------
老大解释得很清楚了,其实你的英文提示也很清楚了.

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