当我运行下面的脚本，它会输出错误信息，我该怎么
- WBOYOriginal
- 2016-06-13 09:54:12850browse
function myfunc($argument) {
echo $argument + 10;
}
$variable = 10;
echo "myfunc($variable) = " . myfunc($variable);
到底是什么原因呢？
要将自定义函数的结果传回，你需要使用return来将结果传回，而不是echo函数。
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