php实现Mongodb自定义方式生成自增ID的方法,mongodbid
本文实例讲述了php实现Mongodb自定义方式生成自增ID的方法。分享给大家供大家参考。具体分析如下:
复制代码 代码如下://首先创建一个自动增长id集合 ids
>db.ids.save({name:"user", id:0});
//可以查看一下是否成功
> db.ids.find();
{ "_id" : ObjectId("4c637dbd900f00000000686c"), "name" : "user", "id" : 0 }
//然后每次添加新用户之前自增一下 ids集合 获得id
>userid = db.ids.findAndModify({update:{$inc:{'id':1}}, query:{"name":"user"}, new:true});
{ "_id" : ObjectId("4c637dbd900f00000000686c"), "name" : "user", "id" : 1 }
//注:因为findAndModify是一个方法完成更新查找两个操作,所以具有原子性,多线程不会冲突。
//然后保存相应的数据
>db.user.save({uid:userid.id, username:"kekeles", password:"kekeles", info:"http://www.bkjia.com/ "});
//查看结果
> db.user.find();
{ "_id" : ObjectId("4c637f79900f00000000686d"), "uid" : 1, "username" : "admin", "password" : "admin" }
//这是mongo的shell,如果用的是服务器端程序java php python,可以自己对这些操作封装一下,只用传几个参数就可以返回自增的id,还可以实现像Oracle的跨表的自增id。
自己写了一段php的,拿出来给大家分享。
<?php function mid($name, $db){ $update = array('$inc'=>array("id"=>1)); $query = array('name'=>$name); $command = array( 'findandmodify'=>'ids', 'update'=>$update, 'query'=>$query, 'new'=>true, 'upsert'=>true ); $id = $db->command($command); return $id['value']['id']; } $conn = new Mongo(); $db = $conn->idtest; $id = mid('user', $db); $db->user->save(array( 'uid'=>$id, 'username'=>'kekeles', 'password'=>'kekeles', 'info'=>'http://www.bkjia.com/ ' )); $conn->close(); ?>
希望本文所述对大家的php程序设计有所帮助。

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