php实现的日历程序,php实现日历程序
本文实例讲述了php实现的日历程序。分享给大家供大家参考。具体如下:
<?php ////判断$Year和$Month是否为空,如果为空就获取系统当前日期,否则用$_GET获取 $Year = empty($_GET['Year']) ? date("Y"): $_GET["Year"]; $Month = empty($_GET['Month']) ? date("m"): $_GET["Month"]; ////获取当前日期//// $Today = date("Ymj"); ////初始化日期数组//// $Maxday = array("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20", "21","22","23","24","25","26","27","28","29","30","31"); $Maxday_count = count($Maxday); ////初始化星期数组//// $Weekday = array("<font color='red'>Sun</font>","Mon","Tue","Wed","Thu","Fri","<font color='red'>Sat</font>"); $Weekday_count = count($Weekday); $daynum = 0; $space = "<td> </td>"; $col = 0; ////打印表格头部//// ?> <form action="calendar.php" method="post" name="linked"> <table><tr><td colspan=3 align=center><a href="?Year=<?php if($Year-1 > 1900)echo $Year-1;else echo $Year;?>&Month=<?php echo $Month?>" onClick="javascript:document.linked.submit();" name="Year"><<</a> <?php echo $Year?> <a href="?Year=<?php if($Year+1 <2999) echo $Year+1;else echo $Year;?>&Month=<?php echo $Month?>" onClick="javascript:document.linked.submit();" name="Year">>></a></td> <td> </td><td colspan=3 align=center><a href="?Year=<?php echo $Year?>&Month=<?php if($Month-1 >0) if($Month-1 < 10)echo "0".($Month-1); else echo $Month-1; else echo $Month;?>" onClick="javascript:document.linked.submit();" name="Month"><<</a> <?php echo $Month;?> <a href="?Year=<?php echo $Year?>&Month=<?php if($Month+1 <13) if($Month+1 <10) echo "0".($Month+1);else echo ($Month+1); else echo $Month;?>" onClick="javascript:document.linked.submit();" name="Month">>></a></td></tr><tr><td colspan="8"></td></tr><tr> <?php ////打印星期列表//// while(list(,$Weekvalue) = each($Weekday)) echo "<td align=center> ".$Weekvalue." </td>"; echo "</tr>"; ////打印日期列表//// //当月份为4,6,9,11的时候,从数组末尾删除一个值,也就是删除31这个值. if($Month == 4 or $Month == 6 or $Month == 9 or $Month == 11) { array_pop($Maxday); $Maxday_count--; } //先判断月份是否为2月,如果是的话再判断年份是否为闰年,如果是的话就从数组尾部移除2个值,否则就移除3个值. if($Month == 2) { if($Year % 4 == 0) { array_pop($Maxday); array_pop($Maxday); $Maxday_count-=2; } else { array_pop($Maxday); array_pop($Maxday); array_pop($Maxday); $Maxday_count-=3; } } ////打印日期//// while($daynum < $Maxday_count) { echo "<tr>"; while(list($colnum,$Dayvalue) = each($Maxday)) { //判断当前日期为一星期中的哪一天 $DayWeek = date("w",strtotime($Year."-".$Month."-".$Dayvalue)); //当当前日期处于第1个,也就是每个月的第1天的时候,在它前面补上相应的空格子 if($Dayvalue == 1) for($i=0;$i<$DayWeek;$i++) echo $space;//打印每个月空出的几个格子 $daynum++; //当打印日期的时候与当前日期字符串进行比较,如果相等就将字体标为红色. if($Year.$Month.$Dayvalue == $Today) { $u1 = "<b><u>"; $u2 = "</b></u>"; } else { $u1 = ""; $u2 = ""; } if($DayWeek == 0 or $DayWeek == 6) $color = "red"; else $color = "black"; echo "<td align=center><font color=".$color."> ".$u1.$Dayvalue.$u2." </font></td>"; //用本周第几天这个值加1,如果是7的倍数就换行退出此轮循环(换行打印) if(($DayWeek+1) % 7 == 0) { $col++; break; } } echo "</tr>"; } ?>
运行效果如下:
希望本文所述对大家的php程序设计有所帮助。

php把负数转为正整数的方法:1、使用abs()函数将负数转为正数,使用intval()函数对正数取整,转为正整数,语法“intval(abs($number))”;2、利用“~”位运算符将负数取反加一,语法“~$number + 1”。

实现方法:1、使用“sleep(延迟秒数)”语句,可延迟执行函数若干秒;2、使用“time_nanosleep(延迟秒数,延迟纳秒数)”语句,可延迟执行函数若干秒和纳秒;3、使用“time_sleep_until(time()+7)”语句。

php除以100保留两位小数的方法:1、利用“/”运算符进行除法运算,语法“数值 / 100”;2、使用“number_format(除法结果, 2)”或“sprintf("%.2f",除法结果)”语句进行四舍五入的处理值,并保留两位小数。

判断方法:1、使用“strtotime("年-月-日")”语句将给定的年月日转换为时间戳格式;2、用“date("z",时间戳)+1”语句计算指定时间戳是一年的第几天。date()返回的天数是从0开始计算的,因此真实天数需要在此基础上加1。

php判断有没有小数点的方法:1、使用“strpos(数字字符串,'.')”语法,如果返回小数点在字符串中第一次出现的位置,则有小数点;2、使用“strrpos(数字字符串,'.')”语句,如果返回小数点在字符串中最后一次出现的位置,则有。

php字符串有下标。在PHP中,下标不仅可以应用于数组和对象,还可应用于字符串,利用字符串的下标和中括号“[]”可以访问指定索引位置的字符,并对该字符进行读写,语法“字符串名[下标值]”;字符串的下标值(索引值)只能是整数类型,起始值为0。

方法:1、用“str_replace(" ","其他字符",$str)”语句,可将nbsp符替换为其他字符;2、用“preg_replace("/(\s|\ \;||\xc2\xa0)/","其他字符",$str)”语句。

在php中,可以使用substr()函数来读取字符串后几个字符,只需要将该函数的第二个参数设置为负值,第三个参数省略即可;语法为“substr(字符串,-n)”,表示读取从字符串结尾处向前数第n个字符开始,直到字符串结尾的全部字符。


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