构建自己的PHP框架--抽象Controller的基类
我们将简单的路由解析和执行，从入口文件public/index.php中移入到框架中。入口文件顿时变得清爽无比～～
但是，去我们的controller里看一下，会看到如下的code：
public function actionView()
{
$body = 'Test body information';
require '../views/site/view.php';
}
难道我们每写一个要去渲染页面的action，都要去找相应路径的view，然后把它require进来。肯定不能这样，所以我们要抽象出一个Controller的基类，实现一个渲染页面的方法，让其他的controller继承，就可以使用相应的方法。
不用说，这个controller的基类肯定要写到框架里。而且也要写两个，一个放在base中，一个放在web中，web中的Controller继承base中的。
先来看在base中的
<?php
namespace sf\base;
/**
* Controller is the base class for classes containing controller logic.
* @author Harry Sun <sunguangjun@126.com>
*/
class Controller
{
}
只有一个空类，等待添加内容。
再来看web中的
<?php
namespace sf\web;
/**
* Controller is the base class for classes containing controller logic.
* @author Harry Sun <sunguangjun@126.com>
*/
class Controller extends \sf\base\Controller
{
/**
* Renders a view
* @param string $view the view name.
* @param array $params the parameters (name-value pairs) that should be made available in the view.
*/
public function render($view, $params = [])
{
extract($params);
return require '../views/' . $view . '.php';
}
}
可以看到，我们首先从数组中把变量导入到当前的符号表中，然后引入相应的view页面。
然后，在SiteController，我们只需要这么写就可以了。
<?php
namespace app\controllers;
use sf\web\Controller;
class SiteController extends Controller
{
public function actionTest()
{
echo 'success!';
}
public function actionView()
{
$this->render('site/view', ['body' => 'Test body information']);
}
}
然后，访问www.Bkjia.com，就可以看到跟之前一样的页面了。
我们来完善一下base中的Controller
<?php
namespace sf\base;
/**
* Controller is the base class for classes containing controller logic.
* @author Harry Sun <sunguangjun@126.com>
*/
class Controller
{
/**
* @var string the ID of this controller.
*/
public $id;
/**
* @var Action the action that is currently being executed.
*/
public $action;
}
添加了两个属性，分别来记录当前的controller和action。
然后，我们要在解析router之后，将其赋值，code如下：
<?php
namespace sf\web;
/**
* Application is the base class for all application classes.
* @author Harry Sun <sunguangjun@126.com>
*/
class Application extends \sf\base\Application
{
/**
* Handles the specified request.
* @return Response the resulting response
*/
public function handleRequest()
{
$router = $_GET['r'];
list($controllerName, $actionName) = explode('/', $router);
$ucController = ucfirst($controllerName);
$controllerNameAll = $this->controllerNamespace . '\\' . $ucController . 'Controller';
$controller = new $controllerNameAll();
$controller->id = $controllerName;
$controller->action = $actionName;
return call_user_func([$controller, 'action'. ucfirst($actionName)]);
}
}
然后我们就可以在controller和view中拿到相应的controller名字和action名字了，将view.php修改如下：
<html>
<head>
<title>title</title>
<head>
<body>
<?php echo $this->id;?><br/>
<?php echo $this->action;?><br/>
<?php echo $body;?>
</body>
</html>
然后我们就可以看到如下的页面了
有人觉得现在大家都前后端分离了，我们不需要用PHP去render一个页面，只需要返回一个josn字符串就好了，这个就更简单了，在web的Controller中添加一个toJson方法即可
/**
* Convert a array to json string
* @param string $data
*/
public function toJson($data)
{
if (is_string($data)) {
return $data;
}
return json_encode($data);
}
将SiteController中的actionTest，修改如下：
public function actionTest()
{
$data = ['first' => 'awesome-php-zh_CN', 'second' => 'simple-framework'];
echo $this->toJson($data);
}
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