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Homephp教程php手册PHP递归创建多级目录(一道面试题的解题过程),php递归

PHP递归创建多级目录(一道面试题的解题过程),php递归

今天看到一道面试题,要写出一个可以创建多级目录的函数:


 

我的第一个感觉就是用递归创建,具体思路如下:

<span>function</span> Directory(<span>$dir</span><span>){

</span><span>    if</span>(<span>is_dir</span>(<span>$dir</span>) || @<span>mkdir</span>(<span>$dir</span>,0777)){ <span>//</span><span>查看目录是否已经存在或尝试创建,加一个@抑制符号是因为第一次创建失败,会报一个&ldquo;父目录不存在&rdquo;的警告。</span>

        <span>echo</span> <span>$dir</span>."创建成功<br>";   <span>//</span><span>输出创建成功的目录</span>
<span>
    }</span><span>else</span><span>{

        </span><span>$dirArr</span>=<span>explode</span>('/',<span>$dir</span>); <span>//</span><span>当子目录没创建成功时,试图创建父目录,用explode()函数以'/'分隔符切割成一个数组</span>

        <span>array_pop</span>(<span>$dirArr</span>); <span>//</span><span>将数组中的最后一项(即子目录)弹出来,</span>

        <span>$newDir</span>=<span>implode</span>('/',<span>$dirArr</span>); <span>//</span><span>重新组合成一个文件夹字符串</span>
<span>
        Directory(</span><span>$newDir</span>); <span>//</span><span>试图创建父目录</span>

        <span>if</span>(@<span>mkdir</span>(<span>$dir</span>,0777<span>)){

            </span><span>echo</span> <span>$dir</span>."创建成功<br>"<span>;

        } </span><span>//</span><span>再次试图创建子目录,成功输出目录名</span>
<span>
    }

}

Directory(</span>"A/B/C/D/E/F");

输出结果如图:


 

但是可以看得出来,写得也太麻烦了,在手册里翻看文件函数,看到一个dirname()函数,其原型如下:

<p>string dirname ( string $path )</p>
<p>给出一个包含有指向一个文件的全路径的字符串,本函数返回去掉文件名后的目录名。 </p>
<p>在 Windows 中,斜线(/)和反斜线(\)都可以用作目录分隔符。在其它环境下是斜线(/)。</p>

可以稍稍地优化一下:

<span>function</span> Directory(<span>$dir</span><span>){

    </span><span>if</span>(<span>is_dir</span>(<span>$dir</span>) || @<span>mkdir</span>(<span>$dir</span>,0777<span>)){ 

        </span><span>echo</span> <span>$dir</span>."创建成功<br>"<span>;   

    }</span><span>else</span><span>{

        Directory(</span><span>dirname</span>(<span>$dir</span><span>));

        </span><span>if</span>(@<span>mkdir</span>(<span>$dir</span>,0777<span>)){

            </span><span>echo</span> <span>$dir</span>."创建成功<br>"<span>;

        }

    }

}</span>

效果一样。


 

之后我在在网上搜一下答案,找到一个异常精辟的:

<span>function</span>  Directory( <span>$dir</span><span> ){    

     </span><span>return</span>   <span>is_dir</span> ( <span>$dir</span> )  or  Directory(<span>dirname</span>( <span>$dir</span> ))  and   <span>mkdir</span> ( <span>$dir</span> , 0777<span>);

}</span>

现在来解释一下整个函数:

先介绍一下PHP中逻辑运算符的优先级顺序:&& > || > and > or,即符号型>字母型,AND型>OR型,所以函数体可以看成:

is_dir ( $dir )  or  (Directory(dirname( $dir ))  and   mkdir ( $dir , 0777));

先判断目标目录是否存在,若存在,依or的短路特性,后面的整体被短路,跳过执行;若目标目录不存在,则执行后面的函数体:

Directory(dirname( $dir ))  and   mkdir ( $dir , 0777) 

我考虑了一下先进行递归的用意:先执行递归,意在确认其父目录(dirname($dir))都已经创建完毕,使后面的mkdir()函数不会创建子目录时找不到父目录发出警告。

进入递归深处后,确认最深处的根目录存在后,从根目录向下依次创建目录。


 

最后,建议要找工作的亲们,去网上找些大公司面试题做一下,毕竟他们考得较为综合较深,在学习知识的时候,也刷一下题,另外也一定要做一下,因为很容易眼高手低,一开始的函数,我优化了好几遍才能正常使用。

以后我也会再找些有意思的面试题跟大家分享。

如果您觉得本博文对您有帮助,您可以推荐或关注我,如果您有什么问题,可以在下方留言讨论,谢谢。

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