PHP中key和current,next的联合运用实例分析,next实例分析
本文实例讲述了PHP中key和current,next的联合运用方法。分享给大家供大家参考,具体如下:
问题:
$arrq = array(); $arrq['tuc'] = array('sss'=>'ewq','shu'=>'sjkah','saa'=>'dwjhaz'); $arrq['tucs'] = array('ssss'=>'ewsq','sQhu'=>dwjhaz','sa12a'=>'dwjQhaz'); $arrq['tuca'] = array('sssd'=>'ewqq','shu2'=>'sjkah','saSa'=>'dwjhhaz');
如何在不破坏数组结构的情况下去除$arrq数组中的重复的值?
思路:先将第一个二维数组中的元素用array_unique函数输出。
输出第二个二维数组中的元素时,自己先用array_unique处理,再去掉在第一个二维数组中已经存在的元素。
输出第三个时,自己先用array_unique处理,再去掉在第一个和第二个二维数组合集中已经存在的元素。
以此类推。
总之,自己先要array_unqiue去重,再去掉自身中在前面所在数组元素合集中存在的元素。
以下为代码:
<?php $arrq = array(); $arrq['tuc'] = array('sss'=>'ewq','shu'=>'sjkah','saa'=>'dwjhaz'); $arrq['tucs'] = array('ssss'=>'ewsq','sQhu'=>'dwjhaz','sa12a'=>'dwjQhaz'); $arrq['tuca'] = array('sssd'=>'ewqq','shu2'=>'sjkah','saSa'=>'dwjhhaz'); $last=array(); //设置一个空的用来比较的数组 while($arr=current($arrq)) { //echo key($arrq); $tmp=array_unique($arr); //先清除每个一维数组自身相同的值 if(count($last)==0) { $last=array_merge($last,$arr); //将已经去重的前面的数组合并 } else { // 对其余一维数组进行输出 //echo key($arrq); foreach($arr as $ke=>$va) { if(in_array($arr[$ke], $last)) //如果已经存在的元素 unset($arrq[key($arrq)][$ke]); //删除,此处取得数组元素的KEY值是关键 } $last=array_merge($last,$arr); //将$last变为前面数组的合集,用来进行下次比较 } next($arrq); //指针向后移,这样才能用key函数取得不同的$arrq的下标 } //以下输出处理后的数组 foreach($arrq as $arr) { foreach($arr as $val) { echo $val." "; } echo "<br>"; } ?>
运行结果为:

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