看了oschina上的两个代码,受益匪浅。其中对join()方法不理解,看python官网文档的介绍:
join([timeout]):等待直到进程结束。这将阻塞正在调用的线程,直到被调用join()方法的线程结束。(好难翻译,应该是这个意思)
哈哈,这个易懂。
join方法,如果一个线程或者一个函数在执行过程中要调用另外一个线程,并且待到其完成以后才能接着执行,那么在调用这个线程时可以使用被调用线程的join方法。
#-*- encoding: gb2312 -*-
import string, threading, time
def thread_main(a):
global count, mutex
# 获得线程名
threadname = threading.currentThread().getName()
for x in xrange(0, int(a)):
# 取得锁
mutex.acquire()
count = count + 1
# 释放锁
mutex.release()
print threadname, x, count
time.sleep(1)
def main(num):
global count, mutex
threads = []
count = 1
# 创建一个锁
mutex = threading.Lock()
# 先创建线程对象
for x in xrange(0, num):
threads.append(threading.Thread(target=thread_main, args=(10,)))
# 启动所有线程
for t in threads:
t.start()
# 主线程中等待所有子线程退出
for t in threads:
t.join()
if __name__ == '__main__':
num = 4
# 创建4个线程
main(4)
###################################################################
#-*- encoding: gb2312 -*-
import threading
import time
class Test(threading.Thread):
def __init__(self, num):
threading.Thread.__init__(self)
self._run_num = num
def run(self):
global count, mutex
threadname = threading.currentThread().getName()
for x in xrange(0, int(self._run_num)):
mutex.acquire()
count = count + 1
mutex.release()
print threadname, x, count
time.sleep(1)
if __name__ == '__main__':
global count, mutex
threads = []
num = 4
count = 1
# 创建锁
mutex = threading.Lock()
# 创建线程对象
for x in xrange(0, num):
threads.append(Test(10))
# 启动线程
for t in threads:
t.start()
# 等待子线程结束
for t in threads:
t.join()
在程序中,最后join()方法的调用就明白了,是主进程挨个调用子线程的join()方法。当四个线程都执行完毕后,主线程才会执行下面的代码,在这里也就是退出了。
相对应的在网上一起找到的另一个方法:
3.守护进程
setDaemon()
这个方法基本和join是相反的。当我们在程序运行中,执行一个主线程,如果主线程又创建一个子线程,主线程和子线程就分兵两路,分别运行,那么当主线程完成想退出时,会检验子线程是否完成。如果子线程未完成,则主线程会等待子线程完成后再退出。但是有时候我们需要的是,只要主线程完成了,不管子线程是否完成,都要和主线程一起退出,这时就可以用setDaemon方法啦

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