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python比较两个列表大小的方法
- WBOYOriginal
- 2016-06-10 15:09:302583browse
本文实例讲述了python比较两个列表大小的方法。分享给大家供大家参考。具体如下：
L1 = [1, ('a', 3)]
L2 = [1, ('a', 2)]
print L1 < L2, L1 == L2, L1 > L2
# less,equal,greater: tuple of results
运行结果如下：
False False True
希望本文所述对大家的Python程序设计有所帮助。
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