Home >Backend Development >Python Tutorial >Python实现简单登录验证

Python实现简单登录验证

WBOY
WBOYOriginal
2016-06-10 15:05:171261browse

本文实例为大家分享了简单的Python登录验证,供大家参考,具体内容如下

编写登录接口

要求:1、输入用户名密码

   2、认证成功后显示欢迎信息

   3、输错三次后锁定

#coding=utf-8
__author__ = 'wangwc'

import sys,os
count = 0
locked = 0
mark_user = 0
mark_passwd = 0
#获取路径
def cur_file_dir():
  path = sys.path[0]
  if os.path.isdir(path):
    return path
  elif os.path.isfile(path):
    return os.path.dirname(path)
#print (cur_file_dir())
path = cur_file_dir()
#print(path)
path1 = path.replace("\\",'/') + '/'
#print (path1)
#path2 = path1 + '/'

#循环输入
while count < 3:
  name = input("Username:").strip()
  if len(name) == 0:
    print ("Username can not be empty....")
    continue
  key = input("Password:").strip()
  if len(key) == 0:
    print("The password can not be empty!Try again...")
    continue
  f = open(path1 + "username.txt","r")
  userlist = f.readlines()
  for user in userlist:
    if user.strip() == name:
      mark_user = 1
  f.close()

  if mark_user == 1:
    f = open(path1 + "%s_lock.txt" %(name),"r")
    locked = int(f.readline().strip())
    f.close()
  else:
    print ("Username or Passsord wrong....")
    break
  if locked == 1:
    print("Sorry, the username had been locked!!!Please call the system administrator...")
  else:
    f = open (path1 + "%s_passwd.txt" %(name),"r")
    passwd = (f.readline().strip())
    if passwd.strip() == key:
      mark_passwd = 1
    if mark_user == 1 and mark_passwd == 1:
      f = open("%s_count.txt" %(name),"w")
      f.write("0")
      f.close()
      print("%s,welcome BABY!" %(name) )
      #input('Press Enter to exit')
    else:
      f = open("%s_count.txt" %(name),"r")
      count = int((f.read().strip()))
      f.close()
      count +=1
      f = open("%s_count.txt" %(name),"w")
      f.write(str(count))
      f.close()
      print ("Username or password wrong!And the username '%s' has %d more chances to retry!" %(name,3 - count))
      if(count == 3):
        print ("'%s' has been locked!!!" %(name))
        if os.path.exists(path1 + "%s_lock.txt" %(name)):
          fobj = open(path1 + "%s_lock.txt" %(name),"w")
          fobj.writelines("1\n")
        else:
          print ("Username or password wrong!")
      continue

以上就是本文的全部内容,希望对大家的学习有所帮助。

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn