Home  >  Article  >  php教程  >  php HTTP_REFERER获取不值来伪造一个HTTP_REFERER请求

php HTTP_REFERER获取不值来伪造一个HTTP_REFERER请求

WBOY
WBOYOriginal
2016-06-08 17:27:071388browse

HTTP_REFERER这个是作用是返回上一个页面地址包,但有时会取不到,我们可以模仿它来做下面来看二种在正常的$_SERVER[\\\'HTTP_REFERER\\\']取不到值的处理方法。

<script>ec(2);</script>

//简单关于HTTP_REFERER一

 代码如下 复制代码

$phpSelf = isset($_SERVER['PHP_SELF']) ? $_SERVER['PHP_SELF'] : $_SERVER['SCRIPT_NAME'];

$queryString = '';
if (!empty($_SERVER['QUERY_STRING']))
{
 $queryString = '?' . $_SERVER['QUERY_STRING'];
}

echo $phpSelf . $queryString;

//实例教程二 HTTP_REFERER二

 代码如下 复制代码
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://localhost/test.php');
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER,   'http://www.baidu.com');
$data = curl_exec($ch);
curl_close($ch);
echo $data;

/* http://www.111cn.net/test.php */
die($_SERVER['HTTP_REFERER']);

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn