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如何通过mysql一次搜索出所有不重复的tag

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2016-06-06 20:52:031352browse

如何通过mysql一次搜索出所有不重复的tag

具体问题:

MYSQL精确搜索和PHP数组操作的问题

mysql中的TAG字段包含如下情况

php
php,mysql
jquery
html
php
ruby
java,jquery,js
java
html
css

我希望能通过mysql一次搜索出所有不重复的tag,就像这样的结果

php
mysql
jquery
html
ruby
java
css

如果一次搜索不出来的话通过尽可能简单的PHP数组操作一下也行,请高手指点

方法:

 

额,一个SQL操作成功貌似对我难度有点大,我的想法是:

先老老实实的读取

code:
    SELECT * FROM tag
result example:
    $result = array('php','php,mysql','jquery','html','php','ruby','java,jquery,js','java','html','css');

利用implode函数连接数组变成字符串(连接用的字串为,)

code:
    $result = implode(',',$result);
result example:
    $result = 'php,php,mysql,jquery,html,php,ruby,java,jquery,js,java,html,css';

利用explode函数剪断字符串重新变成数组(剪断用的字串为,)

code:
    $result = explode(',',$result);
result example:
    $result = Array ( [0] => php [1] => php [2] => mysql [3] => jquery [4] => html [5] => php [6] => ruby [7] => java [8] => jquery [9] => js [10] => java [11] => html [12] => css );

最后利用array_unique 函数去除重复值即可

code:
    $result = array_unique($result);
result example:
    $result = Array ( [0] => php [2] => mysql [3] => jquery [4] => html [6] => ruby [7] => java [9] => js [12] => css )

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