Home > Article > Backend Development > 求这个两个数组的差集?
Array ( [0] => Array ( [id] => 11 [parametername] => 参数名称11 ) )
Array ( [0] => Array ( [id] => 6 [parametername] => 参数名称6 ) [1] => Array ( [id] => 10 [parametername] => 参数名称10 ) [2] => Array ( [id] => 11 [parametername] => 参数名称11 ) [3] => Array ( [id] => 15 [parametername] => 参数编辑 ) [4] => Array ( [id] => 16 [parametername] => 参数20 ) )
Array ( [0] => Array ( [id] => 11 [parametername] => 参数名称11 ) )
Array ( [0] => Array ( [id] => 6 [parametername] => 参数名称6 ) [1] => Array ( [id] => 10 [parametername] => 参数名称10 ) [2] => Array ( [id] => 11 [parametername] => 参数名称11 ) [3] => Array ( [id] => 15 [parametername] => 参数编辑 ) [4] => Array ( [id] => 16 [parametername] => 参数20 ) )
<code>$array1 = array( array('n3'=>'v3', 'n4'=>'v4'), array('n1'=>'v1', 'n2'=>'v2') ); $array2 = array( array('n1'=>'v1', 'n2'=>'v2') ); $result = array_udiff( $array1, $array2, function ($v1, $v2) { return strcmp(serialize($v1), serialize($v2)); } ) // 或者 $result = array_filter($array1, function($v) use ($array2) { return in_array($v, $array2); }); </code>
你可以试试。
回调是你的好朋友。
数据:
<code><?php $array1 = array( array( "id" => 11, "parametername" => "PARAMETER NAME XI" ) , array( "id" => 30, "parametername" => "PARAMETER NAME XXX" ) , ); $array2 = array( array( "id" => 6, "parametername" => "Parameter Name VI" ), array( "id" => 10, "parametername" => "Parameter Name X" ) , array( "id" => 11, "parametername" => "Parameter Name XI" ) , array( "id" => 15, "parametername" => "Parameter Name XV" ) , array( "id" => 16, "parametername" => "Parameter Name XVI" ) , ); </code>
比较代码如下:
<code>array_udiff($array2, $array1, function($a, $b) { return ($a['id'] - $b['id']); }); /* array( array( "id" => 6, "parametername" => "Parameter Name VI" ), array( "id" => 10, "parametername" => "Parameter Name X" ) , array( "id" => 15, "parametername" => "Parameter Name XV" ) , array( "id" => 16, "parametername" => "Parameter Name XVI" ) , ) */ array_udiff($array1, $array2, function($a, $b) { return ($a['id'] - $b['id']); }) /* array( array( "id" => 30, "parametername" => "PARAMETER NAME XXX" ), ) */ </code>
另外我希望没理解错题意。以上代码均认为只要id
相同就属于同一个数据。如果有必要自行更改回调的逻辑。
回调很好。。学了一招。