Home >Backend Development >PHP Tutorial >怎样优雅地拼凑字符串?
<code>$username = $this->username ?: 'someone'; $email = $this->email ?: Yii::$app->params['adminEmail']; $password = Yii::$app->getSecurity()->generatePasswordHash( $this->password ?: 'xx' ); $table = User::tableName(); $auth_key = Yii::$app->security->generateRandomString(); $status = User::STATUS_ACTIVE; $timestamp = time(); $god = 1; $words = "in the ${table} has a record which contains some value : "; $words .= "'${username}', '${email}', '${password}', '${auth_key}', '${status}','${timestamp}', '${god}', '${timestamp}', '${god}' "; </code>
上面的 word 怎样拼凑才能优雅些?
<code>$username = $this->username ?: 'someone'; $email = $this->email ?: Yii::$app->params['adminEmail']; $password = Yii::$app->getSecurity()->generatePasswordHash( $this->password ?: 'xx' ); $table = User::tableName(); $auth_key = Yii::$app->security->generateRandomString(); $status = User::STATUS_ACTIVE; $timestamp = time(); $god = 1; $words = "in the ${table} has a record which contains some value : "; $words .= "'${username}', '${email}', '${password}', '${auth_key}', '${status}','${timestamp}', '${god}', '${timestamp}', '${god}' "; </code>
上面的 word 怎样拼凑才能优雅些?
sprintf
是个不错的方案
不过看你的代码感觉就是像把各种变量都打出来调试用,那么有个神器 get_defined_vars
,变量名变量值都有了你值得拥有
一句话,尽量使用 ORM 或者 数据库类 去操作数据库,而不要人工拼凑字符串,这样能有效防止 SQL注入 的发生。Yii 框架肯定是自带这些东西的,你上文档好好看看就好啦:http://www.yiiframework.com/doc/guide/1.1/en/database.dao#binding-para...
如果是单纯的拼接字符串的话一般情况下双引号内直接写变量名(不用花括号)就可以了,当然介于那个字段的拼接实在是有点丑你可以这么改写一下:
<code>$words = "in the $table has a record which contains some value: "; $words .= implode(", ", array_map(function($item) { return "'$item'"; }, [$username, $email, $password, $auth_key, $status, $timestamp, $god]) ); </code>
存数组遍历呗