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php static变量的refcount为何是2,is_ref为何是1?

WBOY
WBOYOriginal
2016-06-06 20:33:231380browse

<code><?php $a = 1;
    xdebug_debug_zval("a");
    static $b = 1;
    xdebug_debug_zval("b");
?>
</code>

为何执行后输出是
a: (refcount=1, is_ref=0)=1
b: (refcount=2, is_ref=1)=1
static变量和普通变量为何会有这样的区别?

回复内容:

<code><?php $a = 1;
    xdebug_debug_zval("a");
    static $b = 1;
    xdebug_debug_zval("b");
?>
</code>

为何执行后输出是
a: (refcount=1, is_ref=0)=1
b: (refcount=2, is_ref=1)=1
static变量和普通变量为何会有这样的区别?

refcount是计数次数,如果为0 就是被销毁
如果用Unset 这个数会减1
is_ref是表示引用
猜想:这表变量里的内容是另一个内存地址(也就是真实的内容),然后unset只会删除这个变量,并不会删除这个内存地址里面的东西
http://php.net/manual/zh/features.gc.refcounting-basics.php

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