Home > Article > Backend Development > PHP下调用网易云音乐搜索API结果不正确
大家好。
这是网易云音乐的搜索API。
当调用下面一段function,$word是英文时搜索结果正常,但中文的时候返回结果不正确。
为什么呢,请指教?
<code>function music_search($word, $type=1) { $url = "http://music.163.com/api/search/pc"; $post_data = array( 's' => $word, 'offset' => '0', 'limit' => '20', 'type' => $type, ); $referrer = "http://music.163.com/"; $URL_Info = parse_url($url); $values = []; $result = ''; $request = ''; foreach ($post_data as $key => $value) { $values[] = "$key=" . urlencode($value); } $data_string = implode("&", $values); if (!isset($URL_Info["port"])) { $URL_Info["port"] = 80; } $request .= "POST " . $URL_Info["path"] . " HTTP/1.1\n"; $request .= "Host: " . $URL_Info["host"] . "\n"; $request .= "Referer: $referrer\n"; $request .= "Content-type: application/x-www-form-urlencoded\n"; $request .= "Content-length: " . strlen($data_string) . "\n"; $request .= "Connection: close\n"; $request .= "Cookie: " . "appver=1.5.0.75771;\n"; $request .= "\n"; $request .= $data_string . "\n"; $fp = fsockopen($URL_Info["host"], $URL_Info["port"]); fputs($fp, $request); $i = 1; while (!feof($fp)) { if ($i >= 15) { $result .= fgets($fp); } else { fgets($fp); $i++; } } fclose($fp); return $result; } </code>
大家好。
这是网易云音乐的搜索API。
当调用下面一段function,$word是英文时搜索结果正常,但中文的时候返回结果不正确。
为什么呢,请指教?
<code>function music_search($word, $type=1) { $url = "http://music.163.com/api/search/pc"; $post_data = array( 's' => $word, 'offset' => '0', 'limit' => '20', 'type' => $type, ); $referrer = "http://music.163.com/"; $URL_Info = parse_url($url); $values = []; $result = ''; $request = ''; foreach ($post_data as $key => $value) { $values[] = "$key=" . urlencode($value); } $data_string = implode("&", $values); if (!isset($URL_Info["port"])) { $URL_Info["port"] = 80; } $request .= "POST " . $URL_Info["path"] . " HTTP/1.1\n"; $request .= "Host: " . $URL_Info["host"] . "\n"; $request .= "Referer: $referrer\n"; $request .= "Content-type: application/x-www-form-urlencoded\n"; $request .= "Content-length: " . strlen($data_string) . "\n"; $request .= "Connection: close\n"; $request .= "Cookie: " . "appver=1.5.0.75771;\n"; $request .= "\n"; $request .= $data_string . "\n"; $fp = fsockopen($URL_Info["host"], $URL_Info["port"]); fputs($fp, $request); $i = 1; while (!feof($fp)) { if ($i >= 15) { $result .= fgets($fp); } else { fgets($fp); $i++; } } fclose($fp); return $result; } </code>
是不是你用的编码不一样
不正确是什么意思?我测试了下没问题
<code>php</code><code>print_r(json_decode(music_search('十年'),1)); Array ( [result] => Array ( [songCount] => 300 [songs] => Array ( [0] => Array ( [starred] => [popularity] => 100 [starredNum] => 0 [playedNum] => 0 [dayPlays] => 0 [hearTime] => 0 [mp3Url] => http://m1.music.126.net/V6G5ER-inEZ_Oufxq9tmfA==/1153387697546241.mp3 [rtUrls] => Array ( ) [name] => 十年 [id] => 66842 [position] => 4 [duration] => 206000 [status] => 1 [alias] => Array ( ) [commentThreadId] => R_SO_4_66842 [copyFrom] => [album] => Array ( [songs] => Array ( ) [name] => 黑白灰 [id] => 6548 [type] => 专辑 [size] => 10 [status] => 1 [description] => [tags] => [alias] => Array ( ) [company] => 英皇娱乐 [artist] => Array ( [img1v1Id] => 0 [name] => [id] => 0 </code>
估计人家的接口不能接受原生的中文字符的编码。建议在post传入的参数当中,利用urlencode进行转码,再是真正的请求。你可以试试