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Linux下php5.4启动脚本

WBOY
WBOYOriginal
2016-06-06 20:19:411088browse

这篇文章主要介绍了Linux下php5.4启动脚本,需要的朋友可以参考下

废话不多说,直接上步骤
1、修改php-fpm.conf配置文件
修改/usr/local/php/etc/php-fpm.conf(当然这个跟你配置的php路径相关)配置文件

启动pid=run/php-fpm.pid

; Pid file ; Note: the default prefix is /usr/local/php/var ; Default Value: none pid = run/php-fpm.pid

启动error_log=log/php-fpm.log

; Error log file ; If it's set to "syslog", log is sent to syslogd instead of being written ; in a local file. ; Note: the default prefix is /usr/local/php/var ; Default Value: log/php-fpm.log error_log = log/php-fpm.log

2、创建/etc/init.d/php文件

root@aliyun:~# cat /etc/init.d/php #!/bin/bash #Author:iranw #E-mail:wang_wenguan#yeah.net #Website: # pid file pid="/usr/local/php/var/run/php-fpm.pid" # php-fpm path&file phpfpm="/usr/local/php/sbin/php-fpm" param=$1 phpnum=`ps -ef | grep php-fpm | wc -l` if [ "$param" = "stop" ]; then if [ "$phpnum" = "1" ]; then echo "Php process does not exist." exit 1 fi kill `cat $pid` echo "Close php processes. OK" exit 1 fi if [ "$param" = "start" ]; then if [ "$phpnum" != "1" ]; then echo "Php process exist." exit 1 fi $phpfpm echo "Open php processes. OK" exit 1 fi if [ "$param" = "restart" ]; then if [ "$phpnum" = "1" ]; then echo "Php process does not exist. Stop Failed." else kill `cat $pid` for i in `ps -ef | grep php-fpm | grep -v grep | awk {'print $2'}` do kill -9 $i echo "Kill $i successed." done echo "Close php processes. OK" fi $phpfpm if [ "$phpnum" != "1" ]; then echo "Open php processes. OK" else echo "Open php processes. Failed." fi exit 1 fi

3、修改权限

#chmod +x /etc/init.d/php

4、执行结果

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