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PHP实现模仿socket请求返回页面的方法

WBOY
WBOYOriginal
2016-06-06 20:19:001115browse

这篇文章主要介绍了PHP实现模仿socket请求返回页面的方法,是socket通信非常实用的技巧,需要的朋友可以参考下

本文实例讲述了PHP实现模仿socket请求返回页面的方法。分享给大家供大家参考。具体实现方法如下:

复制代码 代码如下:

 $url = "www.XXXX.com";  //自己做替换
 $parse = parse_url($url);  //对URL进行解析,,返回起组成部分。
 $host = $parse['host'];
 $path = $parse['path'];
 $port = 80;
 $timeout = 80;
 $fp = @fsockopen($host, $port, $errno, $errstr, $timeout);  //打开socket链接
 if (!$fp){
     echo $errno."--".$errstr;  //如果错误,则返回错误代码和错误信息
 } else {
     $out = "POST $path HTTP/1.1\r\n";  //以下是HTTP请求头信息
     $out .= "Host: ".$host."\r\n";
     $out .= "Accept: */*\r\n";
     $out .= "Connection: Close\r\n";
     $out .= "Cookie: $cookie\r\n\r\n";
   
     @fwrite($fp, $out);  //把请求信息写到链接中
     $status = stream_get_meta_data($fp);
     if(!$status['timed_out']) {    
                 while (!feof($fp)) { 
                     if(($header = @fgets($fp)) && ($header == "\r\n" ||  $header == "\n")) {    
                         break;    
                     }    
                 }    
        
                 $stop = false;    
                 while(!feof($fp) && !$stop) {    
                     $data = fread($fp,8192);      //8192为可返回字节数
                     $return .= $data;        
                 }    
             }    
     fclose($fp);
     print_r($return);
 }

希望本文所述对大家的PHP程序设计有所帮助。

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