这样写为什么不能获取内容？

<code> <?php $dbhost='';
$dbname='';
$dbuser='';
$dbpass='';
date_default_timezone_set('PRC');
try{$pdo=new PDO('mysql:host='.$dbhost.';dbname='.$dbname,$dbuser,$dbpass);}
catch(Exception $e){die('sql error');}
$pdo->query('SET NAMES utf8');
function cd(){global $pdo;return $pdo->lastInsertId();}
function qr($var){global $pdo;return $pdo->query($var);}
function fo($var){return qr($var)->fetch();}
function fa($var){return qr($var)->fetchALL();}
$fp=fo('SELECT * FROM post WHERE id=1');
echo $fp['title'];
echo $fp['content'];
?></code>

这样写的话页面什么也不现实

回复内容：

<code> <?php $dbhost='';
$dbname='';
$dbuser='';
$dbpass='';
date_default_timezone_set('PRC');
try{$pdo=new PDO('mysql:host='.$dbhost.';dbname='.$dbname,$dbuser,$dbpass);}
catch(Exception $e){die('sql error');}
$pdo->query('SET NAMES utf8');
function cd(){global $pdo;return $pdo->lastInsertId();}
function qr($var){global $pdo;return $pdo->query($var);}
function fo($var){return qr($var)->fetch();}
function fa($var){return qr($var)->fetchALL();}
$fp=fo('SELECT * FROM post WHERE id=1');
echo $fp['title'];
echo $fp['content'];
?></code>

这样写的话页面什么也不现实

<code> <?php $dbhost='';
$dbname='';
$dbuser='';
$dbpass='';
date_default_timezone_set('PRC');
try{$pdo=new PDO('mysql:host='.$dbhost.';dbname='.$dbname,$dbuser,$dbpass);}
catch(Exception $e){die('sql error');}
$pdo->query('SET NAMES utf8');
function cd(){global $pdo;return $pdo->lastInsertId();}
function qr($var){global $pdo;return $pdo->query($var);}
function fo($var)
{
    //问题出在这里，qr($var)的值是$pdo->query($var)的值，是一个sql的执行结果，而不是对象$pdo,调用fetch肯定出错啊
    return qr($var)->fetch(); 
}
function fa($var){return qr($var)->fetchALL();}
$fp=fo('SELECT * FROM post WHERE id=1');
echo $fp['title'];
echo $fp['content'];
?></code>