SQLite Like function


  Translation results：

sqlite

Database; use; embedded relational database

like

英[laɪk] 美[laɪk ]

vt. Like; (used with would or should to express politeness) think; want; like to do

prep. (express attribute) like; (expression method) like; (ask for opinions )...how; (indicating enumeration) such as

adj. similar; identical

n. similar people [things]; preferences; hobbies; (especially those who are regarded as having no Someone or something is so good) kind, type

conj.as;as if;like...the same;as if

adv.such as;(informal spoken language, replacing as)the same as... ; (informal spoken language, used when thinking about the next sentence, explanation or example) probably; maybe

SQLite Like functionsyntax

Function:SQLite's LIKE operator is used to match the text value of the wildcard specified pattern. The LIKE operator returns true, which is 1, if the search expression matches the pattern expression. There are two wildcard characters used with the LIKE operator: The percent sign (%) The underscore (_) The percent sign (%) represents zero, one, or more numbers or characters. An underscore (_) represents a single number or character. These symbols can be used in combination.

Syntax: % and _ The basic syntax is as follows:

SELECT FROM table_name
WHERE column LIKE 'XXXX%'
or
SELECT FROM table_name
WHERE column LIKE '%XXXX%'
or
SELECT FROM table_name
WHERE column LIKE 'XXXX_'
or
SELECT FROM table_name
WHERE column LIKE '_XXXX'
or
SELECT FROM table_name
WHERE column LIKE '_XXXX_'

You can use the AND or OR operator to combine N quantities of conditions. Here, XXXX can be any number or string value.

SQLite Like functionexample

COMPANY 表有以下记录：

ID          NAME        AGE         ADDRESS     SALARY
----------  ----------  ----------  ----------  ----------
1           Paul        32          California  20000.0
2           Allen       25          Texas       15000.0
3           Teddy       23          Norway      20000.0
4           Mark        25          Rich-Mond   65000.0
5           David       27          Texas       85000.0
6           Kim         22          South-Hall  45000.0
7           James       24          Houston     10000.0

sqlite> SELECT * FROM COMPANY WHERE AGE  LIKE '2%';
这将产生以下结果：

ID          NAME        AGE         ADDRESS     SALARY
----------  ----------  ----------  ----------  ----------
2           Allen       25          Texas       15000.0
3           Teddy       23          Norway      20000.0
4           Mark        25          Rich-Mond   65000.0
5           David       27          Texas       85000.0
6           Kim         22          South-Hall  45000.0
7           James       24          Houston     10000.0

sqlite> SELECT * FROM COMPANY WHERE ADDRESS  LIKE '%-%';
这将产生以下结果：

ID          NAME        AGE         ADDRESS     SALARY
----------  ----------  ----------  ----------  ----------
4           Mark        25          Rich-Mond   65000.0
6           Kim         22          South-Hall  45000.0

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