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<p ng-repeat="links in slides">
<p ng-repeat="link in links">{{link.name}}</p>
</p>
slides是一个二维数组,我以上的代码会报错Error: [ngRepeat:dupes]
$http.get('index.php?option=com_mtree&task=ajax.load').success(function(response) {
if(response.status) {
$scope.links = response.links;
if(typeof response.links != 'undefined') {
var slides = [], slide;
for(var i=0; i<response.links.length;) {
slide = [];
for(var c=0; c<3&&c<response.links.length; c++, i++) {
slide.push(response.links.indexOf(i));
}
slides.push(slide);
}
$scope.slides = slides;
}
/*
setTimeout(function(){
jQuery('.saved-list .slideshow').cycle('destroy');
jQuery('.saved-list .slideshow').cycle();
}, 0);
*/
}
});
请问如何实现嵌套?
过去多啦不再A梦2017-05-15 16:51:05
直接的答案:
<p ng-repeat="links in slides">
<p ng-repeat="link in links track by $index">{{link.name}}</p>
</p>
Error: [ngRepeat:dupes]
这个出错提示具体到题主的情况,意思是指数组中有2个以上的相同数字。ngRepeat不允许collection中存在两个相同Id的对象
For example:
item in items
is equivalent toitem in items track by $id(item)
. This implies that the DOM elements will be associated by item identity in the array.
对于数字对象来说,它的id就是它自身的值,因此,数组中是不允许存在两个相同的数字的。为了规避这个错误,需要定义自己的track by表达式。例如:item in items track by item.id
或者item in items track by fnCustomId(item)
。嫌麻烦的话,直接拿循环的索引变量$index来用item in items track by $index
fiddle示例:http://jsfiddle.net/shiedman/PLV6G/