redis排序问题，请各位不吝赐教

Question

redis localhost:6379> sadd userlist 1 
(integer) 1 
redis localhost:6379> sadd userlist 2 
(integer) 1 
redis localhost:6379> sadd userlist 3 
(integer) 1 
redis localhost:6379> sadd userlist 4 
(integer) 1

redis localhost:6379> sadd userlist 5
(integer) 1

redis localhost:6379> set score:user:1 20 
OK 
redis localhost:6379> set score:user:2 15 
OK 
redis localhost:6379> set score:user:3 11 
OK 
redis localhost:6379> set score:user:4 24 
OK

redis localhost:6379> set score:user:5 15
OK


redis localhost:6379> set age:user:1 29 
OK 
redis localhost:6379> set age:user:2 35 
OK 
redis localhost:6379> set age:user:3 25 
OK 
redis localhost:6379> set age:user:4 31

OK

redis localhost:6379> set age:user:5 27
OK

如上redis结构，如何实现sort的时候根据score倒排序，如果score相等（上面user2和user5的score相等），那么按照age正排序？

期望最后得到的userid排序结果为:

4

1

5

2

3

请问各位：这样的命令该如何写，或者有没有比较好的解决方案

Answer 1

你可以考虑下sorted set，set只是集合，本身是无排序的，而sorted set是支持排序的，根据score

Answer 2

sort userlist by score:user:* desc

Answer 3

维护两个zset
按age排序: zadd sort_user_age username age
按score排序： zadd sort_user_score username score

然后把用户的信息以string方式保存，按照某种排序方式然后去mget.

Answer 4

想要排序肯定要用zadd，但是你说的这个比较复杂了，实现得想想