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#<type 'unicode'>
a = '276.30'
b = '1,446.90'
c = '23,456.80'
相加之后,保留2个小数点~
PHP中文网2017-04-18 10:32:43
>>> num=['276.30','1,446.90','23,456.80']
>>> "%.2f" % sum(map(lambda s:float(s.replace(',','')),num))
'25180.00'
>>> '{:,.2f}'.format(sum(map(lambda s:float(s.replace(',','')),num)))
'25,180.00'
阿神2017-04-18 10:32:43
>>> def sum(*args):
... r = 0.0
... for n in args:
... r += float(n)
... return "%.2f" % r
...
>>> sum('1.1', '2.2')
'3.30'
>>> sum('1.1', '2.2', 3.3)
'6.60'
PHP中文网2017-04-18 10:32:43
要看你需要的是显示出来的保留两位小数,还是真实的保留两位小数相加。
前者是
ans_print_version = "{.2f}".format(a + b + c)
后者是
ans = round(a + b + c,2)