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android - Error: java.lang.IndexOutOfBoundsException: Invalid index 2

How to remove the seperator line in footerLayout? I have a footerLayout below the listView, used to display the totalAmount as shown below. If I click the seperator line in footerLayout, my app crashed.

My MainActivity

AllAdapter obj = new AllAdapter(getApplication(), search, listview,imageView,text,button);
footerLayout = (LinearLayout) getLayoutInflater().inflate(R.layout.under_listview, null);
totalAmount = (TextView) footerLayout.findViewById(R.id.amount);

LogCat error

 java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2
            at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
            at java.util.ArrayList.get(ArrayList.java:304)
            at com.example.tony.monthlyexpenses.adapter.AllAdapter.getItem(AllAdapter.java:61)
            at com.example.tony.monthlyexpenses.QuickExpenses$1.onItemClick(QuickExpenses.java:88)
            at android.widget.AdapterView.performItemClick(AdapterView.java:301)

The error pointed to listView onClickListener

 listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                mClickedPosition = position;
                Expenses o = (Expenses) obj.getItem(position);
                String day = o.getDate();
            }
        });

AllAdapter

 public Expenses getItem(int position) {
        return search.get(position);
    }

The footerLayout is supposed to be displayed outside the listView, not inside. How can I get rid of this ?

I also have activity_main.xml, AllAdapter class, all_adapter.xml for ListView and also under_listview.xml for the footerLayout.

activity_main

AllAdapter

under_listview

How to move the footerLayout out from the ListView ?

I add android:footerpidersEnabled="false" now become like this

But still clickable !!!

谁知道问题出在哪?

footerLayout被按时如何不出现灰色?

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Antworte allen(4)Ich werde antworten

  • ringa_lee

    ringa_lee2017-04-17 18:03:43

    很简单,但也很容易出错的问题,加了footer后,你的listview item数量是3,但adapterviewcount其实并没有变成3,所以在你点击footer时执行的是obj.getItem(2),肯定是数组越界异常了。对于添加了header或footer的listview,正确的取item方法应该是

    listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
                public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                    Expenses o = (Expenses) listView.getAdapter().getItem(position);
                    if(o != null){
                        mClickedPosition = position;
                        //Expenses o = (Expenses) obj.getItem(position);
                        String day = o.getDate();
                    }
                }
            });
    

    header或footer属于AdapterView的子viewlistView.getAdapter().getItem(position);能确保你取2的position时不越界,再做对象空判断。

    Antwort
    0
  • 天蓬老师

    天蓬老师2017-04-17 18:03:43

    你不能使用setOnItemClickListener 来作为footview的点击事件,我认为你应该单独的去设置
    例如 footview.setonClickListener(new OnClickListener{}); 祝你好运

    Antwort
    0
  • 伊谢尔伦

    伊谢尔伦2017-04-17 18:03:43

    你这个是数组下标越界了啊,你的数组size是2,所以对应的下标只能是0和1,但是你在使用的时候用了2,错误显示你有个无效的index 2,你自己找下第61行和第88行,看是否有地方调用了index是2的

    Antwort
    0
  • 伊谢尔伦

    伊谢尔伦2017-04-17 18:03:43

    footerLayout移出listView的写法是

    listview.addFooterView(footerLayout, null, false);

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