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SELECT agentid,count(id) AS allnum,
sum(if(review_flag = 'p'AND delflag IN ('N' , 'P'),1,0)) AS approved_1,
sum(if(review_flag = 'E', 1, 0)) AS approved_2,
sum(if(review_mode = '3' AND review_flag = 'Y',1,0)) AS approved_3,
sum(if(review_mode = '2' AND review_flag = 'Y',1,0)) AS approved_4,
sum(if(review_mode = '1' AND review_flag = 'Y',1,0)) AS approved_5,
sum(if(review_flag = 'N' AND resubmit = 'Y',1,0)) AS approved_6,
sum(if(review_flag = 'N' AND resubmit = 'N',1,0)) AS approved_7
FROM talbe WHERE agentid IN ('A' , 'B', 'C') AND delflag IN ('N' , 'P', 'H')
GROUP BY agentid
该语句执行的时候 需要20多S才完成。
伊谢尔伦2017-04-10 15:57:28
调整表结构. 似乎你把很复杂的逻辑放在 数据表结构里了.
多次sum不是问题. 主要在于这个group by上, 一般的, mysql 全表扫一边, 创建临时表, 排序分组. 这个是很慢的. 你可以试一下 建立 (agentid, delflag, review_flag, review_mode, resubmit, id)
的联合索引.
PHPz2017-04-10 15:57:28
这种情况我想应该是索引建立的不够科学吧,你可以借助EXPLAIN
来具体查看什么地方会卡住,是否用到索引。
同时,给你一个建议,你应该把表结构贴出来,这样路过的大神就能具体帮你分析分析了。