Heim  >  Fragen und Antworten  >  Hauptteil

Die MySQL-Triggeranweisung schlägt bei der Variablenzuweisung fehl

Das Folgende ist die Definition der Patiententabelle:

Patients table Columns:
PatientId int AI PK 
FirstName longtext 
LastName longtext 
Email longtext 
NIC longtext 
Phone longtext 
Address longtext 
City longtext 
Country longtext 
DOB datetime(6) 
Gender longtext 
Reference longtext 
SerialNumberYear smallint 
SerialNumber int 
DoctorId int 
CreatedOn datetime(6) 
UpdatedOn datetime(6) 
CreatedBy longtext 
SMS_Allowed tinyint(1)
Email_Allowed tinyint(1) 
SpecialConcern1 longtext 
SpecialConcern2 longtext 
SpecialConcern3 longtext 
SpecialConcern4 longtext 
CustomYearlyId longtext 
YearlyId int

Ich habe den folgenden Trigger für diese Tabelle in MySQL:

CREATE TRIGGER generate_yearly_id BEFORE INSERT ON clinic.patients
       FOR EACH ROW
       BEGIN
           DECLARE last_id INTEGER default 10;
           DECLARE current_year DATE;
           DECLARE yearly_id INTEGER default 0;
           IF NEW.CustomYearlyId IS NULL THEN
           BEGIN
                INSERT INTO DEBUG VALUES (null,"start trigger");
                 #SET @last_id := (SELECT max(yearlyid) FROM patients WHERE 
                 #      YEAR(createdon)=YEAR(CURDATE()));
                IF last_id IS NOT NULL THEN
                BEGIN
                    SET @yearly_id = 1;
                    INSERT INTO DEBUG VALUES (null, concat("in if lastid is not null ",@yearly_id));
                END;
                ELSE
                BEGIN
                    #SET @yearly_id := 1;
                END;
                END IF;
                SET NEW.yearlyid := @yearly_id;
           END;
           END IF;
       END;//
       delimiter ;

Anweisung SET @yearly_id = 1; 工作正常。但是如果我将其更改为 SET @yearly_id = @last_id;, der Trigger schlägt fehl. Was habe ich bei dieser Aufgabe falsch gemacht? last_id hat einen Standardwert. Muss ich ihn also initialisieren?

P粉356361722P粉356361722185 Tage vor282

Antworte allen(1)Ich werde antworten

  • P粉548512637

    P粉5485126372024-04-03 00:09:22

    下面的代码可以完美运行。不同之处是 1. 变量在使用前已被初始化。显然默认值是不够的。 1. 在“if”条件中使用了计数,而不是测试“is null”。

    CREATE TRIGGER generate_yearly_id BEFORE INSERT ON clinic.patients
           FOR EACH ROW
           BEGIN
               DECLARE last_id INTEGER default 0;
               DECLARE current_year DATE;
               DECLARE yearly_id INTEGER default 1;
               declare count INTEGER default 0;
               IF NEW.CustomYearlyId IS NULL THEN
               BEGIN
                    #init last_id to some value before using
                    SET @last_id = 0;
                    SET @yearly_id = 0;
                    #INSERT INTO DEBUG VALUES (null,"start trigger");
                    set @count := (select count(*) from patients where
                            YEAR(CreatedOn)=YEAR(curdate()));
                    IF @count > 0 THEN
                    BEGIN
                        SET @last_id := (SELECT max(yearlyid) FROM patients WHERE 
                           YEAR(createdon)=YEAR(CURDATE()));
                        SET @yearly_id = @last_id + 1;
                        SET NEW.yearlyid := @yearly_id;
                        #INSERT INTO DEBUG VALUES (null, concat("in if lastid is not null ",@yearly_id));
                    END;
                    ELSE
                    BEGIN
                        #INSERT INTO DEBUG VALUES (null, concat("in else ",@yearly_id));
                        #SET @yearly_id = 1;
                        SET NEW.yearlyid := 1;
                    END;
                    END IF;
                    #Set NEW.yearlyid := 1;
               END;
               END IF;
           END;//
           delimiter ;

    Antwort
    0
  • StornierenAntwort