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Ich verwende diese Abfrage, um eine HTML-Tabelle zu erstellen und per E-Mail zu versenden. Ist es nur dann möglich, Zellen zur Verbesserung der Lesbarkeit zusammenzuführen, wenn die Spalten „Gruppen-ID“ und „Gesamttransaktionssumme“ denselben Wert haben? Unten ist das Ergebnis, das ich erhalten möchte
CREATE TABLE #list (GroupID int,AccountID int,Country varchar (20),AccountTransactionSum int)
Insert into #list
values
(1,18754,'United Kingdom',110),
(1,24865,'Germany',265),
(1,82456,'Poland',1445),
(1,98668,'United Kingdom',60),
(1,37843,'France',1490),
(2,97348,'United Kingdom',770)
DECLARE @xmlBody XML
SET @xmlBody = (SELECT (SELECT GroupID, AccountID, Country, AccountTransactionSum, TotalTransactionSum = sum(AccountTransactionSum) over (partition by GroupID)
FROM #list
ORDER BY GroupID
FOR XML PATH('row'), TYPE, ROOT('root')).query('<html><head><meta charset="utf-8"/><style>
table <![CDATA[ {border-collapse: collapse; } ]]>
th <![CDATA[ {background-color: #4CAF50; color: white;} ]]>
th, td <![CDATA[ { text-align: center; padding: 8px;} ]]>
tr:nth-child(even) <![CDATA[ {background-color: #f2f2f2;} ]]>
</style></head>
<body><table border="1" cellpadding="10" style="border-collapse:collapse;">
<thead><tr>
<th>No.</th>
<th> Group ID </th><th> Account ID </th><th> Country </th><th> Account Transaction Sum </th><th> Total Transaction Sum </th>
</tr></thead>
<tbody>
{for $row in /root/row
let $pos := count(root/row[. << $row]) + 1
return <tr align="center" valign="center">
<td>{$pos}</td>
<td>{data($row/GroupID)}</td><td>{data($row/AccountID)}</td><td>{data($row/Country)}</td><td>{data($row/AccountTransactionSum)}</td><td>{data($row/TotalTransactionSum)}</td>
</tr>}
</tbody></table></body></html>'));
select @xmlBody
Die Ergebnisse, die ich erhalten habe
Die Ergebnisse, die ich will
Link zum HTML-Editor https://codebeautify.org/real-time-html-editor/y237bf87d
P粉3109311982024-03-31 14:04:19
对于 Siggemannen 的非常好的答案，我只想添加一种替代方法来处理 xquery 中的那些 td，
SELECT GroupID,
AccountID,
Country,
AccountTransactionSum,
TotalTransactionSum = sum(AccountTransactionSum) over (partition by GroupID),
rowspan = COUNT(*) OVER(PARTITION BY GroupID),
display = CASE WHEN lag(GroupID) OVER(ORDER BY GroupID,AccountID) = GroupID THEN 'display:none' ELSE '' END
FROM #list
定义 rowspan 和 display 后，您可以在 xquery for 循环中使用它们
for $row in /root/row let $pos := count(root/row[. << $row]) + 1 return{$pos} {data($row/GroupID)} {data($row/AccountID)} {data($row/Country)} {data($row/AccountTransactionSum)} {data($row/TotalTransactionSum)}
P粉7544734682024-03-31 12:15:21
这是一个很好的问题，因为我不知道 xquery 可以发挥这种魔力！
这就是我想到的：
DROP TABLE #list
go
SELECT *
INTO #list
FROM (
VALUES
(1,18754,'United Kingdom',110),
(1,24865,'Germany',265),
(1,82456,'Poland',1445),
(1,98668,'United Kingdom',60),
(1,37843,'France',1490),
(2,97348,'United Kingdom',770)
) t (groupid,accountid, country, AccountTransactionSum)
DECLARE @xmlBody XML
SET @xmlBody = (SELECT (SELECT GroupID,
AccountID,
Country,
AccountTransactionSum,
TotalTransactionSum = sum(AccountTransactionSum) OVER (partition BY GroupID),
COUNT(*) OVER(PARTITION BY GroupID) AS rowspan,
CASE WHEN lag(GroupID) OVER(ORDER BY groupid,accountid) = GroupID THEN 1 ELSE 0 END AS skipTd
FROM #list ll
ORDER BY GroupID, accountid
FOR XML PATH('row'), TYPE, ROOT('root')).query('
| No. | Group ID | Account ID | Country | Account Transaction Sum | Total Transaction Sum |
|---|---|---|---|---|---|
| {$pos} | {data($row/AccountID)} | {data($row/Country)} | {data($row/AccountTransactionSum)} | ||
| {$pos} | {data($row/GroupID)} | {data($row/AccountID)} | {data($row/Country)} | {data($row/AccountTransactionSum)} | {data($row/TotalTransactionSum)} |
| {$pos} | {data($row/GroupID)} | {data($row/AccountID)} | {data($row/Country)} | {data($row/AccountTransactionSum)} | {data($row/TotalTransactionSum)} |
基本上我创建了两列，rowspan 和skipTd。第一个控制是否应适用 rowspan，第二个表示是否应跳过当前 然后我向 xquery 添加了一个嵌套的 if ，因此它根据这两个标志返回 rowspanned、“跳过”或正常 HTML。也许有更好的方法，我不是专家。，因为它属于同一组。
Antwort0