Heim > Fragen und Antworten > Hauptteil
Was muss ich in der Abfrage ändern, um überhaupt eine exakte Übereinstimmung zu erhalten?
Wenn zum Beispiel jemand Fröhliches Lied in das Suchformular eingibt, erhält er nun diese Ausgabe..
Glückliches Kind
Schöne Tage
Fröhliche Menschen
Fröhliches Lied
Fröhlicher Bahnhof
...
Das ist meine Frage..
SELECT `artist`, `song`, `genre`, `pass`, `id` FROM `songs` JOIN `artists` USING (`pass`) WHERE MATCH(`artist`) AGAINST("happy song") OR MATCH(`song`, `genre`) AGAINST("happy song") ORDER BY `song` ASC LIMIT 0,30 ') or die(mysql_error($_connect));``` Thank you! EDIT 03.07.22 Changed query to:<br> ```$query = mysqli_query($_connect, ' SELECT `artist`, `song`, `genre`, `pass`, `id` FROM `songs` JOIN `artists` USING (`pass`) WHERE MATCH(`artist`) AGAINST("happy song") OR MATCH(`song`, `genre`) AGAINST("happy song") ORDER BY `song` = "happy song" DESC ') or die(mysql_error($_connect));``` The output is the same, result with only "song" in the text are above in the result when searched for "happy song" **EDIT 14.7.22** **Table Artists:** CREATE TABLE `artists` ( `artist` varchar(40) NOT NULL, `pass` int(10) UNSIGNED NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 PACK_KEYS=1; ALTER TABLE `artists` ADD PRIMARY KEY (`pass`), ADD UNIQUE KEY `uni_que` (`artist`) USING BTREE; ALTER TABLE `artists` ADD FULLTEXT KEY `full_txt` (`artist`); COMMIT; **Table Songs:** CREATE TABLE `songs` ( `song` varchar(80) NOT NULL, `tags` varchar(40) NOT NULL, `style` varchar(20) NOT NULL, `pass` bigint(20) UNSIGNED NOT NULL, `id` bigint(20) UNSIGNED NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 PACK_KEYS=1; ALTER TABLE `songs` ADD PRIMARY KEY (`id`); ALTER TABLE `songs` ADD FULLTEXT KEY `song` (`song`,`tags`,`style`); COMMIT;
P粉1166544952024-03-30 00:57:29
您当前正在要求使用 ORDER BY 歌曲 ASC
按字母顺序排序
更改为 ORDER BY MATCH(...) AGAINST(...) DESC
这可能会将“一首关于快乐孩子的歌曲”放在第一位。也就是说,如果你首先需要“欢歌”,我们就需要更加努力:
SELECT ... FROM ... WHERE ... ORDER BY song = "happy song" DESC, MATCH(...) AGAINST (...)
(由于您有 OR
并涉及多个列,因此查询可能会变得相当混乱。)
如果您不想要只有一个单词的歌曲,请参阅 +
运算符,或者
MATCH(song) AGAINST('+"happy song"')
注意引号的有意使用。