Durchsuchen Sie die JSON-Spalten von Laravel in anderen Tabellen über die Zuordnung

Question

Ich habe versucht, einen Suchcode zu schreiben, und das ist mein Code:

$services = Service::query()->with('plans')->latest();


    if ($request->service_name) {
               $services = $services->whereRaw("CONVERT(JSON_EXTRACT(name, '$.ar') using 'utf8') LIKE  '%$request->service_name%' ")
                ->orWhereRaw("CONVERT(JSON_EXTRACT(name, '$.en') using 'utf8') LIKE  '%$request->service_name%' ")
                ->orWhereRaw("CONVERT(JSON_EXTRACT(name, '$.he') using 'utf8') LIKE  '%$request->service_name%' ");     
    }

        if ($request->plan_name) {
            $plan_name = $request->plan_name;
            $services = $services->whereHas('plans', function ($q) use ($plan_name) {
                $q->where('name->en','Like','%'.$plan_name.'%');
            });
       }

        return $services->get();

Aber wenn ich plan_name in der Anfrage sende, filtert der Code nach Dienstname statt nach Planname

Ich habe versucht, Daten nach Plannamen zu filtern, als ich den Plannamencode in der Anfrage gesendet habe, aber es funktioniert nicht

Answer 1

if ($request->service_name && !$request->plan_name) { // When only service name provided
    $services = $services->whereRaw("CONVERT(JSON_EXTRACT(name, '$.ar') using 'utf8') LIKE  '%$request->service_name%' ")
            ->orWhereRaw("CONVERT(JSON_EXTRACT(name, '$.en') using 'utf8') LIKE  '%$request->service_name%' ")
            ->orWhereRaw("CONVERT(JSON_EXTRACT(name, '$.he') using 'utf8') LIKE  '%$request->service_name%' ");
}

if ($request->plan_name && !$request->service_name) { // When only plan name provided
    $plan_name = $request->plan_name;
    $services = $services->whereHas('plans', function ($q) use ($plan_name) {
        $q->where('name->en','Like','%'.$plan_name.'%');
    });
}