suchen

Heim  >  Fragen und Antworten  >  Hauptteil

Warum kann PHP die hochgeladene Datei nicht sehen?

Ich habe ein index.phpupload.php。在 index. 中是一个 form action="upload.php" ,其中包含 input type="file" id="file" name="file"-Tag. Der PHP-Code lautet:

<?php
$file = $_FILES['file'];
print_r($file);
echo "test";
?>

Aus irgendeinem Grund zeigt es, dass echoprint_r() nicht funktioniert.

Ich habe versucht, den Code neu zu schreiben. Das Hinzufügen anderer Bezeichner in index.php 内为 input-Tags funktioniert aber immer noch nicht. Was habe ich falsch gemacht?

P粉356361722P粉356361722302 Tage vor405

Antworte allen(2)Ich werde antworten

  • P粉080643975

    P粉0806439752024-01-17 15:55:50

    您没有提及正在上传的文件类型。这是图像上传的示例。允许选择多个图像。

    <form action="upload.php" method="post" enctype="multipart/form-data">
    Get a Photo from your device <br>
    <input type="file" name="image1[]" multiple accept="image/png, image/jpeg, image/gif, image/webp" /><br>
    <button type="submit">Upload Photo</button>
    </form>

    以及上传PHP:

    foreach ($_FILES["image1"]["error"] as $key => $error) {
        if ($error == 0 ) {
            $tmp_name = $_FILES["image1"]["tmp_name"][$key];
            $name = basename($_FILES["image1"]["name"][$key]);
            $result = move_uploaded_file($tmp_name, "$uploads_dir/$name");
            if($result == false){echo "not moved\n";}
        }
        if($error > 0){echo "error $error\n";}
    }

    要确定上传的图像类型:

    switch(strtolower($_FILES['image1']['type'])){
      case 'image/jpeg':
        $image = @imagecreatefromjpeg($_FILES['image1']['tmp_name']);
        if ($image !== false){$save = true;break;}
      case 'image/png':
        $image = @imagecreatefrompng($_FILES['image1']['tmp_name']);
        if ($image !== false){$save = true;break;}
      case 'image/gif':
        $image = @imagecreatefromgif($_FILES['image1']['tmp_name']);
        if ($image !== false){$save = true;break;}
      case 'image/webp':
        $image = @imagecreatefromwebp($_FILES['image1']['tmp_name']);
        if ($image !== false){$save = true;break;}
      default:
        $img = @getimagesize($_FILES['image1']['tmp_name']);
        switch(strtolower($img['mime'])){
        case 'image/jpeg':
          $image = @imagecreatefromjpeg($_FILES['image1']['tmp_name']);
          if ($image !== false){$save = true;break;}
        case 'image/png':
          $image = @imagecreatefrompng($_FILES['image1']['tmp_name']);
          if ($image !== false){$save = true;break;}
        case 'image/gif':
          $image = @imagecreatefromgif($_FILES['image1']['tmp_name']);
          if ($image !== false){$save = true;break;}
        default:
          $filename = $_FILES['image1']['name'];
          $ext = substr($filename,-3);
          switch(strtolower($ext)){
          case 'jpg':
            $image = @imagecreatefromjpeg($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
          case 'ebp':
            $image = @imagecreatefromwebp($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
          case 'gif':
            $image = @imagecreatefromgif($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
          case 'png':
            $image = @imagecreatefrompng($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
          default:
            $image = @imagecreatefromjpeg($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
            $image = @imagecreatefrompng($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
            $image = @imagecreatefromgif($_FILES['image1']['tmp_name']);
            if ($image !== false){$save = true;break;}
          }
        }
      }

    Antwort
    0
  • P粉321676640

    P粉3216766402024-01-17 00:50:31

    你忘记了 enctype="multipart/form-data"

    尝试这个版本

    <form action="upload.php" method="post" enctype="multipart/form-data">
      <p><input type="file" name="file">
      <p><button type="submit">Submit</button>
    </form>
    
    
    
    

    Antwort
    0
  • StornierenAntwort