Warum werden nur die Ergebnisse der ersten Datenbankabfrage angezeigt und die Funktionalität der zweiten Abfrage ignoriert?

Question

Die folgende Ausgabe zeigt die Ergebnisse der ersten Abfrage, jedoch nicht die der zweiten Abfrage. Wenn ich eine Abfrage ohne Verwendung einer Funktion durchführe, funktioniert es einwandfrei.

function builtFooter($catactive, $catlink)
{
    global $conn;
    $sql = "SELECT catid, catname_de AS name, catlink as link, extern, extlink FROM categories WHERE catactive=? AND catlink!=? ORDER BY catsort";
    $stmt = $conn->prepare($sql);
    $stmt->bind_param("ss", $catactive, $catlink);
    $stmt->execute();
    $result = $stmt->get_result();
    while ($cat = $result->fetch_assoc()) {
        $resArr[] = $cat;
        echo '
' . $cat['name'] . '
';

        $cities = "SELECT COUNT(a.ad_id) AS ANZ,a.region, b.city, b.citylink FROM ads a, neueorte b WHERE a.zeigen=? AND a.gesperrt=? AND FIND_IN_SET(?, a.portale) AND a.catid=? AND b.po_id=a.region GROUP BY a.region ORDER BY ANZ DESC LIMIT 0,50";
        $stmt = $conn->prepare($cities);
        $zeigen = 'ja';
        $gesperrt = 'no';
        $category = $cat['catid'];
        $stmt->bind_param("ssss", $zeigen, $gesperrt, $portalnumber, $category);
        $stmt->execute();
        $result = $stmt->get_result();
        while ($city = $result->fetch_assoc()) {
            $resArr[] = $city;
            echo ' ' . $city['city'] . ' 
';
        }
    }
}

builtFooter('yes', 'markt');

Answer 1

这些查询都正常工作，并且我得到了想要的结果：

$catactive = 'yes';
$catlink = 'markt';
$sql = "SELECT catid, catname_de AS name, catlink as link, extern, extlink FROM categories WHERE catactive=? AND catlink!=? ORDER BY catsort";
        $stmt = $conn->prepare($sql); 
        $stmt->bind_param("ss", $catactive, $catlink);
        $stmt->execute();
        $result = $stmt->get_result();
        while ($cat = $result->fetch_assoc()) {    
            $resArr[] = $cat;
           echo '<h3><a href="'.$cat['link'].'" title="'.$cat['name'].' bei $portalname">'.$cat['name'].'</a></h3>';
        
        $cities = "SELECT COUNT(a.ad_id) AS ANZ,a.region, b.city, b.citylink FROM ads a, neueorte b WHERE a.zeigen=? AND a.gesperrt=? AND FIND_IN_SET(?, a.portale) AND a.catid=? AND b.po_id=a.region GROUP BY a.region ORDER BY ANZ DESC LIMIT 0,50";
        $stmt = $conn->prepare($cities); 
        $zeigen = 'ja';
        $gesperrt = 'no';
        $category = $cat['catid'];
        $stmt->bind_param("ssss", $zeigen, $gesperrt, $portalnumber, $category);
        $stmt->execute();
        $r = $stmt->get_result();
        while ($city = $r->fetch_assoc()) {    
            $resArr[] = $city;
            echo' '.$city['city'].' <br />';
        }
       }

但是当我构建一个函数时，我无法得到第二个查询的结果：

function builtFooter($catactive,$catlink){
        global $conn;
            $sql = "SELECT catid, catname_de AS name, catlink as link, extern, extlink FROM categories WHERE catactive=? AND catlink!=? ORDER BY catsort";
            $stmt = $conn->prepare($sql); 
            $stmt->bind_param("ss", $catactive, $catlink);
            $stmt->execute();
            $result = $stmt->get_result();
            while ($cat = $result->fetch_assoc()) {    
                $resArr[] = $cat;
               echo '<h3><a href="/sexkontakte/'.$cat['link'].'" title="'.$cat['name'].' bei $portalname">'.$cat['name'].'</a></h3>';
            
            $cities = "SELECT COUNT(a.ad_id) AS ANZ,a.region, b.city, b.citylink FROM ads a, neueorte b WHERE a.zeigen=? AND a.gesperrt=? AND FIND_IN_SET(?, a.portale) AND a.catid=? AND b.po_id=a.region GROUP BY a.region ORDER BY ANZ DESC LIMIT 0,50";
            $stmt = $conn->prepare($cities); 
            $zeigen = 'ja';
            $gesperrt = 'no';
            $category = $cat['catid'];
            $stmt->bind_param("ssss", $zeigen, $gesperrt, $portalnumber, $category);
            $stmt->execute();
            $r = $stmt->get_result();
            while ($city = $r->fetch_assoc()) {    
                $resArr[] = $city;
                echo' '.$city['city'].' <br />';
    }
    }
       }
       builtFooter('yes','markt');

我有categories、ads和neueorte这些表。我想构建页脚链接，所以我想将类别作为h3标签，然后按城市分组，其中有放置广告的城市。希望我做得对，我是这个页面的新手。