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Was soll ich tun, wenn bei der Überprüfung des PHP-Formulars in Zeile 21 der Hinweis: Undefinierter Index: E-Mail in F:\Apache\Apache24\htdocs\chap01\form1.php angezeigt wird?

<!DOCTYPE html PUBLIC "-//W3C//DTD ;html xmlns="http://www.w3.org/1999/xhtml">

<head>

<title>表单验证</title>

<meta http-equiv=" Content-Type" content="text/html; charset=utf-8" />

<meta name="description" content="" />

<meta name="keywords" content=" " />

<script type="text/javascript">


</script>


<style type="text/css">

</ style>

</head>

    <body>

    <?php

$name = $email =$gender =$comment = $website ="";


if($_SERVER ["REQUEST_METHOD"] == "POST"){

    $name = test_input($_POST["name"]);

    $email = test_input($_POST["email"]);

    $website = test_input ($_POST["website"]);

    $comment = test_input($_POST["comment"]);

    $gender = test_input($_POST["gender"])；

}

function test_input( $data){

    $data = trim($data);

    $data = stripeslashes($data);

    $data = htmlspecialchars($data);

    return $data;

}

?> ;


<h2> php 验证实列</h2>

<form method="post" action ="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">

姓名:< Eingabetyp = „Text“ Name = „Name“>

<br><br> br>

网址:<input type="text" website ="website">

<br><br>

评论:<input type="text" comment = "comment">

<br><br>

性别:

<input type="radio" name ="gender" vlaue ="female">女性

<input type="radio" name =" Geschlecht" vlaue="männlich">男性

<br><br>

<input type="submit" name="submit" value = "提交">

</form>

<?php

echo "<h2>您的输入为：</h2>";


echo "<br>";

echo $name;

echo "< br>";

echo $email;

echo "<br>";

echo $website;

echo "<br>";

echo $comment;

echo "<br>";

echo $gender;

? >

    </body>

</html>


WW2564 Tage vor1453

Antworte allen(2)Ich werde antworten

  • 乘易网络

    乘易网络2017-11-17 16:37:28

    input 的email 没有name属性 服务端怎么获取？

    Antwort
    0
  • phpcn_u61612

    phpcn_u616122017-11-17 14:34:41

    QQ截图20171117142103.png

    QQ截图20171117142130.png

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>表单验证</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="description" content="" />
<meta name="keywords" content="" />
<script type="text/javascript">
</script>
<style type="text/css">
</style>
</head>
<body>
<?php
$name = $email = $gender =$comment = $website ="";
if($_SERVER["REQUEST_METHOD"] == "POST"){
    $name = test_input($_POST["name"]);
    $email = test_input($_POST["email"]);
    $website = test_input($_POST["website"]);
    $comment = test_input($_POST["comment"]);
    $gender = test_input($_POST["gender"]);
}
function test_input($data){
    $data = trim($data);
    $data = stripslashes($data);
    $data = htmlspecialchars($data);
    return $data;
}
?>
<h2> php 验证实列</h2>
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
姓名:<input type="text" name="name">
<br><br>
电邮:<input type="text" name="email">
<br><br>
网址:<input type="text" name="website">
<br><br>
评论:<input type="text" name="comment">
<br><br>
性别:
<input type="radio" name="gender" vlaue ="female">女性
<input type="radio" name="gender" vlaue ="male">男性
<br><br>
<input type="submit" name="submit" value = "提交">
</form>
<?php
echo "<h2>您的输入为：</h2>";
echo "<br>";
echo $name;
echo "<br>";
echo $email;
echo "<br>";
echo $website;
echo "<br>";
echo $comment;
echo "<br>";
echo $gender;
?>
</body>
</html>


    Antwort
    1
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