So vergleichen Sie zwei Arrays in Javascript

Question

Array a

[{key:1,name:'name1'},{key:2,name:'name2'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'}]

Array b ist Teil von Array a

[{key:1,name:'name1'},{key:2,name:'name2'}]

Array c wird basierend auf Array b modifiziert

[{key:1,name:'name11'},{key:22,name:'name22'}]

Das nun erforderliche Endergebnis besteht darin, dass Schlüssel:1 geändert, Schlüssel:2 gelöscht, Schlüssel:3, Schlüssel:4 und Schlüssel:5 unverändert beibehalten werden und Schlüssel:22 hinzugefügt wird

[{key:1,name:'name11'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'},{key:22,name:'name22'}]

Bitte sagen Sie mir, wie ich diese Logik umsetzen kann

Answer 1

你是要比较还是合并？合并用 deepmerge 很方便

Answer 2

//引入Lodash
_.extend(_.difference(a, b), c)

Answer 3

var a = [{key:1,name:'name1'},{key:2,name:'name2'},{key:3,name:'name3'},{key:4,name:'name4'},{key:5,name:'name5'}];
var b = [{key:1,name:'name1'},{key:2,name:'name2'}];
var c = [{key:1,name:'name11'},{key:22,name:'name22'}];
var d = [];
d = $.extend(a,(b,c));
console.log(d);

extend方法 跟git 的merge差不多
我那样写应该会得到你最后想要的那种结果

Answer 4

function compare(val1,val2){
    if(val1 < val2){
        return 1;
    }else if(val1 > val2){
        return -1;
    }else{
        return 0;
    }
}

var  values = [1,2,50,60,10,20,80];
values.sort(compare);
alert(values); //80,60,50,20,10,2,1

Answer 5

如果找不到好的工具，或者不想污染命名空间，那就把数组解耦，这样应该可以满足你的要求

let a = [{ key: 1, name: 'name1' }, { key: 3, name: 'name3' }, { key: 2, name: 'name2' }, { key: 4, name: 'name4' }, { key: 5, name: 'name5' }];
let b = [{ key: 1, name: 'name1' }, { key: 2, name: 'name2' }];
let c = [{ key: 22, name: 'name22' }, { key: 1, name: 'name11' }];
let akeys = a.map(x => x.key);
let aname = a.map(x => x.name)
let bkeys = b.map(x => x.key)//1,2
let bname = b.map(x => x.name)
let ckeys = c.map(x => x.key)//1,22
let cname = c.map(x => x.name)

ckeys.forEach(function (key, index) {
  if (bkeys.includes(key))
    a[akeys.indexOf(key)].name = cname[ckeys.indexOf(key)]
  else {
    a[akeys.indexOf(bkeys[1])].key = key
    a[akeys.indexOf(bkeys[1])].name = cname[ckeys.indexOf(key)]
  }
})
console.log(a)

Answer 6

给你一段代码拿去想象（只适用与数组合并），将下面的代码拿到控制台输出一下就行了

function arrayExtends(){
    var arrs = Array.prototype.slice.call(arguments);

    if(arrs.length < 2){
        return arrs[0];
    }

    var save = arrs.pop(),
        now;

    while(now = arrs.pop()){
        for( var i = 0 , len = save.length; i < len; i++ ){
            now[i] = save[i];
        }
        save = now;
    }

       return save;
}
arrayExtends([1,2,3,6,7],[4,5,{hello:"world"}],[{key:1,name:"zz"}]);

然后修改下适应你的需求：

function arrayExtends(){
    var arrs = Array.prototype.slice.call(arguments);

    if(arrs.length < 2){
        return arrs[0];
    }

    var save = arrs.pop(),
        now;

    while(now = arrs.pop()){
        for( var i = 0 , len = save.length; i < len; i++ ){
            now[i] = save[i];
        }
        save = now;
    }

    var result = save.sort(function(a,b){
        return a.key - b.key;
    });

       return result;
}
arrayExtends([{key:1,name:"zz"}],[{key:2,name:"zz"},{key:3,name:"zz"}]);