javascript - Wie lösche ich übereinstimmende Array-Elemente in JS?

Question

var arr =  [

  {
    ServiceID: 'go-storage-127.0.0.1-8080-9090',
    ServiceName: 'storage',
    },
  {
    ServiceID: 'System-xxx-192.168.0.111-8000-8000',
    ServiceName: 'xxx',
    },
  {
    ServiceID: 'System-xxx2-192.168.0.111-8000-8000',
    ServiceName: 'xxx2',
     },
  {
    ServiceID: 'System-xxx3-192.168.0.111-8000-8000',
    ServiceName: 'xxx3',
     },
    {
        ServiceID: 'System2-xxx3-192.168.0.111-8000-8000',
        ServiceName: 'xxx3',
       },

    {
        ServiceID: 'test-xxx3-192.168.0.111-8000-8000',
        ServiceName: 'xxx3',
        }];

    将arr数组中ServiceID以test或者System开头的数组元素删掉
    用删掉的方法总是没法讲匹配到的全删，哪位高手能帮个忙呢？谢谢！

Answer 1

arr = arr.filter(item => !(/^test|^System/i.test(item.ServiceID)))

Answer 2

var startsWithArr = strArr => str => {
    return strArr.some(e => str.startsWith(e)); 
}

var starts = startsWithArr([
    'test',
    'System-'
]);

var filterArr = arr => {
    arr.filter(e => !starts(e.ServiceID)); 
}

Answer 3

用Array.filter方法，将过滤后的数组赋值回arr；

arr = arr.filter(function(item) {
    return !(/^(test|System)/g.test(item.ServiceId || ''));
});