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Ich versuche, die Baidu Voice Cloud API zu verwenden, um einen Desktop-Dienst einschließlich TTS zu implementieren. MP3 wurde erfolgreich abgerufen und in cStringIO zwischengespeichert, aber ich weiß nicht, wie ich es abspielen soll. Die Codewiedergabe löst einen Fehler aus.
Beziehen Sie sich auf pywave/pyaudio/pyglet und andere Methoden, die unter http://guzalexander.com/2012/... erwähnt werden.
Der Code lautet wie folgt:
#!/usr/bin/env python
#encoding=utf-8
#import wave
import pyaudio
import pyglet
import urllib, urllib2, pycurl
import base64
import json
import cStringIO
import binascii
## get access token by api key & secret key
def get_token():
apiKey = "xxxxxxxxxx"
secretKey = "yyyyyyyyyyyyyyyyyyyyy"
auth_url = "https://openapi.baidu.com/oauth/2.0/token?grant_type=client_credentials&client_id=" + apiKey + "&client_secret=" + secretKey;
res = urllib2.urlopen(auth_url)
json_data = res.read()
return json.loads(json_data)['access_token']
def dump_res(buf):
#print buf
pass
## post audio to server
def use_cloud(token):
fp = wave.open('vad_0.wav', 'rb')
nf = fp.getnframes()
f_len = nf * 2
audio_data = fp.readframes(nf)
cuid = "xxxxxxxxxx" #my xiaomi phone MAC
srv_url = 'http://vop.baidu.com/server_api' + '?cuid=' + cuid + '&token=' + token
http_header = [
'Content-Type: audio/pcm; rate=8000',
'Content-Length: %d' % f_len
]
c = pycurl.Curl()
c.setopt(pycurl.URL, str(srv_url)) #curl doesn't support unicode
#c.setopt(c.RETURNTRANSFER, 1)
c.setopt(c.HTTPHEADER, http_header) #must be list, not dict
c.setopt(c.POST, 1)
c.setopt(c.CONNECTTIMEOUT, 30)
c.setopt(c.TIMEOUT, 30)
c.setopt(c.WRITEFUNCTION, dump_res)
c.setopt(c.POSTFIELDS, audio_data)
c.setopt(c.POSTFIELDSIZE, f_len)
c.perform() #pycurl.perform() has no return val
def get_audio(token):
cuid = "00030DAF5784" # MAC address
text = "从前有座山,山上有个庙,庙里有个老和尚和小和尚,老和尚对小和尚说:"
#baidu_url = "http://tsn.baidu.com/text2audio?tex=" + urllib.urlencode(text) + "&lan=zh&cuid=" + cuid + "&ctp=1&tok=" + token
baidu_url = "http://tsn.baidu.com/text2audio?tex=" + urllib.quote(text) + "&lan=zh&cuid=" + cuid + "&ctp=1&tok=" + token
print("URL:\t{0}".format(baidu_url))
buf = cStringIO.StringIO()
c = pycurl.Curl()
c.setopt(c.URL, str(baidu_url)) #curl doesn't support unicode
#c.setopt(c.HTTPHEADER, http_header) #must be list, not dict
#c.setopt(c.GET, 1)
c.setopt(c.WRITEFUNCTION, buf.write)
c.setopt(c.CONNECTTIMEOUT, 30)
c.setopt(c.TIMEOUT, 30)
c.setopt(c.WRITEFUNCTION, dump_res)
c.perform() #pycurl.perform() has no return val
#print "type:\t{0}".format(c.CONTENT_TYPE)
print(c.getinfo(c.CONTENT_TYPE))
#print buf.getvalue()
song = pyglet.media.load(buf)
song.play()
buf.close()
if __name__ == "__main__":
token = get_token()
print("token:\t{0}".format(token))
#use_cloud(token)
get_audio(token)
Der ausgegebene Fehler lautet wie folgt:
Traceback (most recent call last):
File "C:\BOM_Planner\source\soldering_assistant_mvp.py", line 87, in <module>
get_audio(token)
File "C:\BOM_Planner\source\soldering_assistant_mvp.py", line 79, in get_audio
song = pyglet.media.load(buf)
File "C:\Python27\lib\site-packages\pyglet\media\__init__.py", line 1429, in load
source = get_source_loader().load(filename, file)
File "C:\Python27\lib\site-packages\pyglet\media\__init__.py", line 1410, in load
return riff.WaveSource(filename, file)
File "C:\Python27\lib\site-packages\pyglet\media\riff.py", line 185, in __init__
file = open(filename, 'rb')
TypeError: coercing to Unicode: need string or buffer, cStringIO.StringO found
黄舟2017-05-18 10:54:15
你写的Python3就推荐pygame,可以用pygame.mixen.music来播放本地mp3文件。
当时我也找了很多都没有成功,最后用pygame播放的。
这是我写的一个例子。可以看看,我是把网络音乐保存到本地mp3文件再播放的,readme里面有相关信息。
https://github.com/kompasim/p...