javascript - Reguläre Übereinstimmung mit mehreren Werten und Rückgabe der angegebenen Gruppe

Question

[
  {
    "thumbURL": "http://img0.imgtn.bdimg.com/it/u=3025588030,3916696758&fm=23&gp=0.jpg",
    "adType": "0",
    "middleURL": "http://img0.imgtn.bdimg.com/it/u=3025588030,3916696758&fm=23&gp=0.jpg",
    "largeTnImageUrl": "",
    "hasLarge": 0,
    "hoverURL": "http://img0.imgtn.bdimg.com/it/u=3025588030,3916696758&fm=23&gp=0.jpg",
    "pageNum": 0,
    "objURL": "http://pic.58pic.com/58pic/13/89/42/50B58PICbPR_1024.jpg",
    "fromURL": "ippr_z2C$qAzdH3FAzdH3Fooo_z&e3Bcbrtv_z&e3Bv54AzdH3Frf1AzdH3F8nbl9dca_z&e3Bip4s",
    "fromURLHost": "www.58pic.com",
    "currentIndex": "",
    "width": 1024,
    "height": 625,
    "type": "jpg",
    "filesize": "",
    "bdSrcType": "0",
    "di": "166108309290",
    "is": "0,0",
    "bdSetImgNum": 0,
    "spn": 0,
    "bdImgnewsDate": "1970-01-01 08:00",
    "fromPageTitle": "<strong>广州<\/strong>夜景图片",
    "bdSourceName": "",
    "bdFromPageTitlePrefix": "",
    "isAspDianjing": 0,
    "token": "",
    "imgType": "",
    "adid": "0",
    "pi": "0",
    "cs": "3025588030,3916696758",
    "os": "442898692,2704726703",
    "simid": "4271495673,765344659",
    "source_type": "",
    "personalized": "0",
    "base64": '',
    "adPicId": "0"
  },
  {
    "thumbURL": "http://img3.imgtn.bdimg.com/it/u=986014556,2144085313&fm=23&gp=0.jpg",
    "adType": "0",
    "middleURL": "http://img3.imgtn.bdimg.com/it/u=986014556,2144085313&fm=23&gp=0.jpg",
    "largeTnImageUrl": "",
    "hasLarge": 0,
    "hoverURL": "http://img3.imgtn.bdimg.com/it/u=986014556,2144085313&fm=23&gp=0.jpg",
    "pageNum": 1,
    "objURL": "http://img.pconline.com.cn/images/upload/upc/tx/itbbs/1010/27/c2/5665647_1288194725363_1024x1024it.jpg",
    "fromURL": "ippr_z2C$qAzdH3FAzdH3Ftpkkf_z&e3Brv5gstgj_z&e3Bv54_z&e3BvgAzdH3F1vAzdH3F8da9988b_z&e3Bip4s",
    "fromURLHost": "itbbs.pconline.com.cn",
    "currentIndex": "",
    "width": 850,
    "height": 609,
    "type": "jpg",
    "filesize": "",
    "bdSrcType": "0",
    "di": "181589344090",
    "is": "0,0",
    "bdSetImgNum": 0,
    "spn": 0,
    "bdImgnewsDate": "1970-01-01 08:00",
    "fromPageTitle": "新鲜出炉《<strong>广州<\/strong>花城广场》+ 广州 塔",
    "bdSourceName": "",
    "bdFromPageTitlePrefix": "",
    "isAspDianjing": 0,
    "token": "",
    "imgType": "",
    "adid": "0",
    "pi": "0",
    "cs": "986014556,2144085313",
    "os": "1860476025,1446613078",
    "simid": "3378049948,192663593",
    "source_type": "",
    "personalized": "0",
    "base64": '',
    "adPicId": "0"
  },
  {
    "thumbURL": "http://img5.imgtn.bdimg.com/it/u=1201045279,2807563612&fm=23&gp=0.jpg",
    "adType": "0",
    "middleURL": "http://img5.imgtn.bdimg.com/it/u=1201045279,2807563612&fm=23&gp=0.jpg",
    "largeTnImageUrl": "",
    "hasLarge": 0,
    "hoverURL": "http://img5.imgtn.bdimg.com/it/u=1201045279,2807563612&fm=23&gp=0.jpg",
    "pageNum": 2,
    "objURL": "http://uploadfile.bizhizu.cn/2015/0314/20150314112515522.jpg",
    "fromURL": "ippr_z2C$qAzdH3FAzdH3F4_z&e3Bktzitz7_z&e3BvgAzdH3FktzitAzdH3F9b0n_z&e3Bip4s",
    "fromURLHost": "m.bizhizu.cn",
    "currentIndex": "",
    "width": 1920,
    "height": 1200,
    "type": "jpg",
    "filesize": "",
    "bdSrcType": "0",
    "di": "99549879990",
    "is": "0,0",
    "bdSetImgNum": 0,
    "spn": 0,
    "bdImgnewsDate": "1970-01-01 08:00",
    "fromPageTitle": "<strong>广州<\/strong>夜景图2",
    "bdSourceName": "",
    "bdFromPageTitlePrefix": "",
    "isAspDianjing": 0,
    "token": "",
    "imgType": "",
    "adid": "0",
    "pi": "0",
    "cs": "1201045279,2807563612",
    "os": "1767325581,810579076",
    "simid": "4162119815,795645113",
    "source_type": "",
    "personalized": "0",
    "base64": '',
    "adPicId": "0"
  }]

Die Quelldaten haben das oben genannte Format. Ich möchte die Daten in objURL und fromPageTitle abgleichen

Der reguläre Ausdruck, den ich selbst geschrieben habe, sieht so aus

"objURL":"(.*?) "fromPageTitle":"(.*?)"

Aber das Matching-Ergebnis objURL enthält andere Zeichen zwischen objURL und fromPageTitle.

Ich kann also nur einen sekundären Matching durchführen.
Entschuldigung, gibt es eine Möglichkeit, den Link hinter objURL und fromPageTitle gleichzeitig abzugleichen?

Answer 1

这么规整的json数据，为什么不用json来操作呢？

Answer 2

a = 字符串
for i in re.findall(r'("objURL.*?fromPageTitle".*?),', a, re.S):
    print i
    

Answer 3

你知道分组的概念吗，匹配完可以把括号中的内容取出来的，java中对应的是Matcher.group(n)