Heim  >  Artikel  >  Backend-Entwicklung  >  Ausführliche Erläuterung von Beispielen für zwei Probleme beim Zusammenführen von XML in der Android-Entwicklung

Ausführliche Erläuterung von Beispielen für zwei Probleme beim Zusammenführen von XML in der Android-Entwicklung

Y2J
Y2JOriginal
2017-04-25 10:38:382622Durchsuche

方法一Dom4J处理XML

import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStream;

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.io.SAXReader;
import org.dom4j.io.XMLWriter;
 
 * 合并并输出2个xml文档,所需要jar:dom4j-1.6.1.jar,jaxen-1.1.1.jar
 * 将某个xml文档的某个标签下或该标签上一级下所有内容插入到另一个xml文档的某个标签下
 * @date 2011-04-13
 * @author RobotJi
 * @version 1.0

 public class UniteXML {
 
 public UniteXML() {}
 
   * 根据is获取doc,这里的is可以是本地流或者网络流
  * @param is
  * @return
  
 public static Document getDocument(InputStream is){
  Document doc=null;
   try {
    doc=new SAXReader().read(is);
   } catch (DocumentException e) {
    e.printStackTrace();
   }
  
  return doc;
 }
 public static InputStream getInputStream(String path){
  File f=new File(path);
  if(!f.exists()){
   return null;
  }
  InputStream is=null;
  try {
   is = new FileInputStream(f);
  } catch (FileNotFoundException e) {
   e.printStackTrace();
  }
  return is;
 }
 
 
  * 获取子Element
  * @param doc 要获取的文档
  * @param tagName 文档对应的标签
  * @return
  
 public Element getSubElement(Document doc,String tagName){
  Element el=(Element)doc.selectSingleNode("//"+tagName);
  return el;
 }
 
 
  * 输出xml文档
  * @param doc 要输出的文档
  * @param fileName 路径
  
 public void writeXML(Document doc,String fileName){
  try {
   XMLWriter writer=new XMLWriter(new FileWriter(fileName));
   writer.write(doc);
   writer.flush();
   writer.close();
  } catch (IOException e) {
   e.printStackTrace();
  }
 }
 
 
  * 合并doc
  * @param path1 主文档
  * @param path2 被合并的文档
  * @param tagName1 在主文档中要插入的标签
  * @param tagName2 被合并文档的标签
  * @param isContain 是否包含被合并文档标签的上一级标签下的所有结点
  * @return
  
 public Document unitXMl(String path1,String path2,String tagName1,String tagName2,boolean isContain){
  Document doc1=getDocument(getInputStream(path1));
  Document doc2=getDocument(getInputStream(path2));
    
  Element elSub2=getSubElement(doc2,tagName2);
  Element elSub1=getSubElement(doc1,tagName1);
  
  if(isContain){
//   doc1.getRootElement().appendContent(elSub2.getParent());//直接插入的根标签下
   elSub1.appendContent(elSub2.getParent());//插入到tagName1标签下
  }else{
//   doc1.getRootElement().appendContent(elSub2);
   elSub1.appendContent(elSub2);
  }
  return doc1;
 }
 
 public static void main(String[] args) {
  UniteXML ux=new UniteXML();
//将c标签下所有内容插入到aa标签下,若参数设为true则可将c标签上一级下的所有内容插入到aa标签下
  Document doc=ux.unitXMl("F:\\test\\a.xml", "F:\\test\\b.xml", "aa", "c", false);
    ux.writeXML(doc, "F:\\test\\a_test.xml");
 }
}

//测试用的2个xml如下:

a.xml

Ausführliche Erläuterung von Beispielen für zwei Probleme beim Zusammenführen von XML in der Android-Entwicklung


方法二:

import java.io. *; //Java基础包,包含各种IO操作   
import java.util. *; //Java基础包,包含各种标准数据结构操作   
import javax.xml.parsers. *; //XML解析器接口   
import org.w3c.dom. *; //XML的DOM实现   
import javax.xml.transform. *;  
import javax.xml.transform.dom. *;  
import javax.xml.transform.stream. *;  
  
/** 
 * XML文件合并工具类 
 
 * @author GhostFromHeaven 
 */  
public class XMLMergeUtil {  
      
    /** 
     * XML文件的合并处理 
     * @param mainFileName 待合并处理的xml文件,合并后将更新此文件 
     * @param subFilename 被合并的xml文件 
     * @return 合并成功返回true,否则返回false 
     * @throws Exception 
     */  
    public static boolean isMerging(String mainFileName, String subFilename)  
            throws Exception {  
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();  
        DocumentBuilder db = null;  
        try {  
            db = dbf.newDocumentBuilder();  
        } catch (ParserConfigurationException pce) {  
            System.err.println(pce); // 出现异常时,输出异常信息  
        }  
        Document doc_main = null;  
        Document doc_vice = null;  
        // 获取两个XML文件的Document  
        try {  
            doc_main = db.parse(mainFileName);  
            doc_vice = db.parse(subFilename);  
        } catch (DOMException dom) {  
            System.err.println(dom.getMessage());  
        } catch (Exception ioe) {  
            System.err.println(ioe);  
        }  
        // 获取两个文件的根节点  
          
        Element root_main = doc_main.getDocumentElement();  
        Element root_vice = doc_vice.getDocumentElement();  
        // 下面添加被合并文件根节点下的每个节点  
        NodeList messageItems = root_vice.getChildNodes();  
        int item_number = messageItems.getLength();  
        // 如果去掉根节点下的第一个节点,那么i从3开始,否则i从1开始  
        for (int i = 1; i < item_number; i = i + 2) {  
            // 调用dupliate(),依次复制被合并XML文档中根节点下的节点  
            Element messageItem = (Element) messageItems.item(i);  
            dupliate(doc_main, root_main, messageItem);  
        }  
        // 调用 write To(),将合并得到的Document写入目标XML文档  
        boolean isWritten = writeTo(doc_main, mainFileName);  
        return isWritten;  
    }  
      
    /** 
     * 
     * @param doc_dup 
     * @param father 
     * @param son 
     * @return 
     * @throws Exception 
     */  
    private static boolean dupliate(Document doc_dup, Element father, Element son)  
            throws Exception {  
        boolean isdone = false;  
        Element parentElement = null;  
          
        DuplicateChildElementObject childElementObject = isChildElement(father, son);  
        if(!childElementObject.isNeedDuplicate()){  
            //节点相同不用合并  
            isdone = true;  
            parentElement = childElementObject.getElement();  
        }else if(childElementObject.getElement() != null){  
            parentElement = childElementObject.getElement();  
        }else{  
            parentElement = father;  
        }  
          
        String son_name = son.getNodeName();  
        Element subITEM = null;  
        if(!isdone){  
            subITEM = doc_dup.createElement(son_name);  
            // 复制节点的属性  
            if (son.hasAttributes()) {  
                NamedNodeMap attributes = son.getAttributes();  
                for (int i = 0; i < attributes.getLength(); i++) {  
                    String attribute_name = attributes.item(i).getNodeName();  
                    String attribute_value = attributes.item(i).getNodeValue();  
                    subITEM.setAttribute(attribute_name, attribute_value);  
                }  
            }  
            parentElement.appendChild(subITEM);  
        }  
        else{  
            subITEM = parentElement;  
        }  
          
        // 复制子结点  
        NodeList sub_messageItems = son.getChildNodes();  
        int sub_item_number = sub_messageItems.getLength();  
        if (sub_item_number < 2) {  
            // 如果没有子节点,则返回  
            isdone = true;  
        } else {  
            for (int j = 1; j < sub_item_number; j = j + 2) {  
                // 如果有子节点,则递归调用本方法  
                Element sub_messageItem = (Element) sub_messageItems.item(j);  
                isdone = dupliate(doc_dup, subITEM, sub_messageItem);  
            }  
        }  
          
          
        return isdone;  
    }  
  
    private static boolean writeTo(Document doc, String fileName) throws Exception {  
        boolean isOver = false;  
        DOMSource doms = new DOMSource(doc);  
        File f = new File(fileName);  
        StreamResult sr = new StreamResult(f);  
        try {  
            TransformerFactory tf = TransformerFactory.newInstance();  
            Transformer t = tf.newTransformer();  
            Properties properties = t.getOutputProperties();  
            properties.setProperty(OutputKeys.ENCODING, "UTF-8");  
            t.setOutputProperties(properties);  
            t.transform(doms, sr);  
            isOver = true;  
        } catch (TransformerConfigurationException tce) {  
            tce.printStackTrace();  
        } catch (TransformerException te) {  
            te.printStackTrace();  
        }  
        return isOver;  
    }  
      
    private static DuplicateChildElementObject isChildElement(Element father, Element son){  
          
        DuplicateChildElementObject  childElementObject = new DuplicateChildElementObject();  
          
        NodeList messageItems = father.getChildNodes();  
        int item_number = messageItems.getLength();  
        //首先遍历所有节点,查找是否有完全相同的节点,防止同一节点已定义多次  
        for (int i = 1; i < item_number; i = i + 2) {  
            Element messageItem = (Element) messageItems.item(i);  
            if(!messageItem.getNodeName().equals(son.getNodeName())){  
                continue;  
            }  
            if(messageItem.isEqualNode(son)){//同时判断子节点是否一致  
                childElementObject.setNeedDuplicate(false);  
                childElementObject.setElement(messageItem);  
                return childElementObject;  
            }  
        }  
        for (int i = 1; i < item_number; i = i + 2) {  
            Element messageItem = (Element) messageItems.item(i);  
            //判断节点是否处于同一级别  
            if(!messageItem.getNodeName().equals(son.getNodeName())){  
                continue;  
            }  
            if(isEqualNode(messageItem,son)){//仅判断当前节点是否一致  
                if(hasEqualAttributes(messageItem,son)){//当前节点完全相同不需要合并  
                    childElementObject.setNeedDuplicate(false);  
                    childElementObject.setElement(messageItem);  
                    return childElementObject;  
                }else{//当前节点的属性不相同,需要合并  
                    childElementObject.setNeedDuplicate(true);  
                    childElementObject.setElement(father);  
                    return childElementObject;  
                }  
            }      
        }  
        //目标文档该节点不存在,需要合并到目标文档中  
        childElementObject.setNeedDuplicate(true);  
        childElementObject.setElement(father);  
        return childElementObject;  
    }  
      
    /** 
     * 判断两个节点是否相同,未判断节点的属性 
     * @param arg0 
     * @param arg 
     * @return 
     */  
    private static boolean isEqualNode(Node arg0,Node arg) {  
        if (arg == arg0) {  
            return true;  
        }  
        if (arg.getNodeType() != arg0.getNodeType()) {  
            return false;  
        }  
  
        if (arg0.getNodeName() == null) {  
            if (arg.getNodeName() != null) {  
                return false;  
            }  
        } else if (!arg0.getNodeName().equals(arg.getNodeName())) {  
            return false;  
        }  
  
        if (arg0.getLocalName() == null) {  
            if (arg.getLocalName() != null) {  
                return false;  
            }  
        } else if (!arg0.getLocalName().equals(arg.getLocalName())) {  
            return false;  
        }  
  
        if (arg0.getNamespaceURI() == null) {  
            if (arg.getNamespaceURI() != null) {  
                return false;  
            }  
        } else if (!arg0.getNamespaceURI().equals(arg.getNamespaceURI())) {  
            return false;  
        }  
  
        if (arg0.getPrefix() == null) {  
            if (arg.getPrefix() != null) {  
                return false;  
            }  
        } else if (!arg0.getPrefix().equals(arg.getPrefix())) {  
            return false;  
        }  
  
        if (arg0.getNodeValue() == null) {  
            if (arg.getNodeValue() != null) {  
                return false;  
            }  
        } else if (!arg0.getNodeValue().equals(arg.getNodeValue())) {  
            return false;  
        }  
        return true;  
    }  
      
    /** 
     * 判断节点的属性是否相同 
     * @param arg0 
     * @param arg 
     * @return 
     */  
    private static boolean hasEqualAttributes(Node arg0,Node arg) {  
          
        NamedNodeMap map1 = arg0.getAttributes();  
        NamedNodeMap map2 = arg.getAttributes();  
        int len = map1.getLength();  
        if (len != map2.getLength()) {  
            return false;  
        }  
          
         for (int i = 0; i < len; i++) {  
             Node n1 = map1.item(i);  
             if(n1.getNodeName() != null){  
                  Node n2 = map2.getNamedItem(n1.getNodeName());  
                  if(n2 == null){  
                      return false;  
                  }else if(!n1.getNodeValue().equals(n2.getNodeValue())){  
                      return false;  
                  }  
             }  
         }  
         return true;  
    }  
    public static void main(String[] args) {  
        try {  
  
            String sourcefile = "d:/a.xml";   
            String targetfile = "d:/b.xml";  
              
            boolean isdone = XMLMergeUtil.isMerging(sourcefile, targetfile);  
              
            if (isdone)  
                System.out.println("XML files have been merged.");  
            else  
                System.out.println("XML files have NOT been merged.");  
          
        } catch (Exception e) {  
            e.printStackTrace();  
        }  
    }  
}  
  
/** 
 * 复制子节点对象 
 * @author Administrator 
 * 
 */  
class DuplicateChildElementObject{  
    private boolean needDuplicate = true;//记录该节点是否需要复制  
    private Element element = null;//记录该节点的父节点  
  
    public DuplicateChildElementObject() {  
        super();  
    }  
  
    public boolean isNeedDuplicate() {  
        return needDuplicate;  
    }  
  
    public void setNeedDuplicate(boolean needDuplicate) {  
        this.needDuplicate = needDuplicate;  
    }  
  
    public Element getElement() {  
        return element;  
    }  
  
    public void setElement(Element element) {  
        this.element = element;  
    }  
}

Das obige ist der detaillierte Inhalt vonAusführliche Erläuterung von Beispielen für zwei Probleme beim Zusammenführen von XML in der Android-Entwicklung. Für weitere Informationen folgen Sie bitte anderen verwandten Artikeln auf der PHP chinesischen Website!

Stellungnahme:
Der Inhalt dieses Artikels wird freiwillig von Internetnutzern beigesteuert und das Urheberrecht liegt beim ursprünglichen Autor. Diese Website übernimmt keine entsprechende rechtliche Verantwortung. Wenn Sie Inhalte finden, bei denen der Verdacht eines Plagiats oder einer Rechtsverletzung besteht, wenden Sie sich bitte an admin@php.cn