Heim  >  Artikel  >  Backend-Entwicklung  >  Android字符串格式化开源库phrase介绍_PHP教程

Android字符串格式化开源库phrase介绍_PHP教程

WBOY
WBOYOriginal
2016-07-13 10:18:15994Durchsuche

Android字符串格式化开源库phrase介绍

在上一篇博客Android通过String.format格式化(动态改变)字符串资源的显示内容中介绍了通过String.format来格式化string.xml文件中的字符串,本文介绍一个可以实现同样功能的开源库phrase,相比于String.format,通过phrase格式化字符串代码更具可读性。


一、phrase项目介绍:

1、源码:phrase项目的源代码很简单,里面总共只有一个类:Phrase.java,代码如下:

/*
 * Copyright (C) 2013 Square, Inc.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
package com.uperone.stringformat;

import java.util.HashMap;
import java.util.HashSet;
import java.util.Map;
import java.util.Set;

import android.app.Fragment;
import android.content.Context;
import android.content.res.Resources;
import android.text.SpannableStringBuilder;
import android.view.View;

/**
 * A fluent API for formatting Strings. Canonical usage:
 * <pre class="code">
 *   CharSequence formatted = Phrase.from("Hi {first_name}, you are {age} years old.")
 *       .put("first_name", firstName)
 *       .put("age", age)
 *       .format();
 * 
*
    *
  • Surround keys with curly braces; use two {{ to escape.
  • *
  • Keys start with lowercase letters followed by lowercase letters and underscores.
  • *
  • Spans are preserved, such as simple HTML tags found in strings.xml.
  • *
  • Fails fast on any mismatched keys.
  • *
* The constructor parses the original pattern into a doubly-linked list of {@link Token}s. * These tokens do not modify the original pattern, thus preserving any spans. *

* The {@link #format()} method iterates over the tokens, replacing text as it iterates. The * doubly-linked list allows each token to ask its predecessor for the expanded length. */ public final class Phrase { /** The unmodified original pattern. */ private final CharSequence pattern; /** All keys parsed from the original pattern, sans braces. */ private final Set keys = new HashSet(); private final Map keysToValues = new HashMap(); /** Cached result after replacing all keys with corresponding values. */ private CharSequence formatted; /** The constructor parses the original pattern into this doubly-linked list of tokens. */ private Token head; /** When parsing, this is the current character. */ private char curChar; private int curCharIndex; /** Indicates parsing is complete. */ private static final int EOF = 0; /** * Entry point into this API. * * @throws IllegalArgumentException if pattern contains any syntax errors. */ public static Phrase from(Fragment f, int patternResourceId) { return from(f.getResources(), patternResourceId); } /** * Entry point into this API. * * @throws IllegalArgumentException if pattern contains any syntax errors. */ public static Phrase from(View v, int patternResourceId) { return from(v.getResources(), patternResourceId); } /** * Entry point into this API. * * @throws IllegalArgumentException if pattern contains any syntax errors. */ public static Phrase from(Context c, int patternResourceId) { return from(c.getResources(), patternResourceId); } /** * Entry point into this API. * * @throws IllegalArgumentException if pattern contains any syntax errors. */ public static Phrase from(Resources r, int patternResourceId) { return from(r.getText(patternResourceId)); } /** * Entry point into this API; pattern must be non-null. * * @throws IllegalArgumentException if pattern contains any syntax errors. */ public static Phrase from(CharSequence pattern) { return new Phrase(pattern); } /** * Replaces the given key with a non-null value. You may reuse Phrase instances and replace * keys with new values. * * @throws IllegalArgumentException if the key is not in the pattern. */ public Phrase put(String key, CharSequence value) { if (!keys.contains(key)) { throw new IllegalArgumentException("Invalid key: " + key); } if (value == null) { throw new IllegalArgumentException("Null value for '" + key + "'"); } keysToValues.put(key, value); // Invalidate the cached formatted text. formatted = null; return this; } /** @see #put(String, CharSequence) */ public Phrase put(String key, int value) { if (!keys.contains(key)) { throw new IllegalArgumentException("Invalid key: " + key); } keysToValues.put(key, Integer.toString(value)); // Invalidate the cached formatted text. formatted = null; return this; } /** * Silently ignored if the key is not in the pattern. * * @see #put(String, CharSequence) */ public Phrase putOptional(String key, CharSequence value) { return keys.contains(key) ? put(key, value) : this; } /** @see #put(String, CharSequence) */ public Phrase putOptional(String key, int value) { return keys.contains(key) ? put(key, value) : this; } /** * Returns the text after replacing all keys with values. * * @throws IllegalArgumentException if any keys are not replaced. */ public CharSequence format() { if (formatted == null) { if (!keysToValues.keySet().containsAll(keys)) { Set missingKeys = new HashSet(keys); missingKeys.removeAll(keysToValues.keySet()); throw new IllegalArgumentException("Missing keys: " + missingKeys); } // Copy the original pattern to preserve all spans, such as bold, italic, etc. SpannableStringBuilder sb = new SpannableStringBuilder(pattern); for (Token t = head; t != null; t = t.next) { t.expand(sb, keysToValues); } formatted = sb; } return formatted; } /** * Returns the raw pattern without expanding keys; only useful for debugging. Does not pass * through to {@link #format()} because doing so would drop all spans. */ @Override public String toString() { return pattern.toString(); } private Phrase(CharSequence pattern) { curChar = (pattern.length() > 0) ? pattern.charAt(0) : EOF; this.pattern = pattern; // A hand-coded lexer based on the idioms in "Building Recognizers By Hand". // http://www.antlr2.org/book/byhand.pdf. Token prev = null; Token next; while ((next = token(prev)) != null) { // Creates a doubly-linked list of tokens starting with head. if (head == null) head = next; prev = next; } } /** Returns the next token from the input pattern, or null when finished parsing. */ private Token token(Token prev) { if (curChar == EOF) { return null; } if (curChar == '{') { char nextChar = lookahead(); if (nextChar == '{') { return leftCurlyBracket(prev); } else if (nextChar >= 'a' && nextChar = 'a' && curChar data); /** Returns the number of characters after expansion. */ abstract int getFormattedLength(); /** Returns the character index after expansion. */ final int getFormattedStart() { if (prev == null) { // The first token. return 0; } else { // Recursively ask the predecessor node for the starting index. return prev.getFormattedStart() + prev.getFormattedLength(); } } } /** Ordinary text between tokens. */ private static class TextToken extends Token { private final int textLength; TextToken(Token prev, int textLength) { super(prev); this.textLength = textLength; } @Override void expand(SpannableStringBuilder target, Map data) { // Don't alter spans in the target. } @Override int getFormattedLength() { return textLength; } } /** A sequence of two curly brackets. */ private static class LeftCurlyBracketToken extends Token { LeftCurlyBracketToken(Token prev) { super(prev); } @Override void expand(SpannableStringBuilder target, Map data) { int start = getFormattedStart(); target.replace(start, start + 2, "{"); } @Override int getFormattedLength() { // Replace {{ with {. return 1; } } private static class KeyToken extends Token { /** The key without { and }. */ private final String key; private CharSequence value; KeyToken(Token prev, String key) { super(prev); this.key = key; } @Override void expand(SpannableStringBuilder target, Map data) { value = data.get(key); int replaceFrom = getFormattedStart(); // Add 2 to account for the opening and closing brackets. int replaceTo = replaceFrom + key.length() + 2; target.replace(replaceFrom, replaceTo, value); } @Override int getFormattedLength() { // Note that value is only present after expand. Don't error check because this is all // private code. return value.length(); } } }


2、字符串格式化原理:

通过阅读Phrase.java的代码可知,它用"{"和"}"将需要格式化的内容包起来,然后用键值对给需要改变的内容传值,包起来的内容为键,值为动态设置的内容,比如:

"Hi {first_name}, you are {age} years old."
我们要最终的显示内容为:“Hi UperOne, you are 26 years old.”这里的first_name和age是键,值为UperOne和26。


二、使用方法:

Phrase.java的类名上面的注释已经告诉了我们具体的使用方法:

/**
 * A fluent API for formatting Strings. Canonical usage:
 * 
 *   CharSequence formatted = Phrase.from("Hi {first_name}, you are {age} years old.")
 *       .put("first_name", firstName)
 *       .put("age", age)
 *       .format();
 * 
*
    *
  • Surround keys with curly braces; use two {{ to escape.
  • *
  • Keys start with lowercase letters followed by lowercase letters and underscores.
  • *
  • Spans are preserved, such as simple HTML tags found in strings.xml.
  • *
  • Fails fast on any mismatched keys.
  • *
* The constructor parses the original pattern into a doubly-linked list of {@link Token}s. * These tokens do not modify the original pattern, thus preserving any spans. *

* The {@link #format()} method iterates over the tokens, replacing text as it iterates. The * doubly-linked list allows each token to ask its predecessor for the expanded length. */ public final class Phrase
比如:

CharSequence parseStr = Phrase.from("Hi {first_name}, you are {age} years old.")
				 .put("first_name", "UperOne")
				 .put("age", "26")
				 .format();
		
mParseTxt.setText( parseStr );
用起来非常简单。



www.bkjia.comtruehttp://www.bkjia.com/PHPjc/885681.htmlTechArticleAndroid字符串格式化开源库phrase介绍 在上一篇博客Android通过String.format式化(动态改变)字符串资源的显示内容中介绍了通过String.format来式...
Stellungnahme:
Der Inhalt dieses Artikels wird freiwillig von Internetnutzern beigesteuert und das Urheberrecht liegt beim ursprünglichen Autor. Diese Website übernimmt keine entsprechende rechtliche Verantwortung. Wenn Sie Inhalte finden, bei denen der Verdacht eines Plagiats oder einer Rechtsverletzung besteht, wenden Sie sich bitte an admin@php.cn